answersLogoWhite

0

First, you need to melt the ice. Look up the heat of fusion of ice, and multiply that by the amount of grams.Then you need to heat the water, from zero degrees to 78 degrees. Look up the specific heat of water, and then multiply together all of the following: The specific heat; the mass; the temperature difference.

Finally, add the two together.

User Avatar

Wiki User

7y ago

What else can I help you with?

Continue Learning about Natural Sciences

How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?

The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.


How many calories are required to heat 37.4g of lead from 15 to 60 degrees Celsius?

This heat is 51, 33 cal.


How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?

To melt ice, the energy required is known as the heat of fusion, which is 334 J/g. To convert this to calories, we need to divide by 4.184 J/cal. So, the total calories required to melt a 25g ice cube at 0 degrees Celsius would be 25g x 334 J/g ÷ 4.184 J/cal = 1991 calories.


How many Calories are needed to heat up a 2 liter bottle of liquid from 0 degrees to 100 degrees Celsius?

It depends on the liquid contained in the bottle and the material the bottle is constructed from. The definition of a Calorie is the amount of energy required to raise the temperature of one gram of water by one degree Celsius, therefore to heat 2 litres of water (which weighs 2000g) by 100 degrees C = 200.000 Calories. N.B. The water will be at 100 C, to convert into steam, the energy required for phase change must be considered. The effect of the bottle has been ignored in this answer. To add to the confusion: This definition is the "real" calorie as defined and used in physics and chemistry etc. The calorie used in food, exercise etc is really a kilocalory. It is abbreviated kcal, but is often read as calories, not kilokalories. If you mix this up, you get the wrong answer that a liter of cola contains approx 430 calories, but to heat it from 7 to 37 degrees celcius takes 30.000 calories.


How many calories are in a food that contains 20 grams of carbohydrate 8 grams protein and 5 grams of fat?

Carbohydrates provide 4 calories per gram, protein provides 4 calories per gram, and fat provides 9 calories per gram. So, the total number of calories in the food would be (20 grams carbohydrate x 4) + (8 grams protein x 4) + (5 grams fat x 9) = 80 + 32 + 45 = 157 calories.

Related Questions

How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?

Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories


How many calories would be needed to melt 10 grams of ice at 0 degrees C?

To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.


How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?

(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.


How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?

38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total


How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?

q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories


How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?

1370 calories


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?

The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.


How many calories to heat 10 ml of water from 25 degrees to 35 degrees C?

100


How many calories are required to raise 8 grams of water 7 degrees Celsius?

The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.


How many calories are into grams?

Grams of what?


How many calories are in 26 grams of carbohydrates?

How many calories are in 26 grams of carbohydrates?"