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You use Heat of fusion... Heat=mass x heat of fusion

Heat of fusion for water: 80 cal/g so

35g x 80 cal/g= 2800 cal released.

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Q: How many calories are released when 35 grams of water at 0 degrees freezes?
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If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?

To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.


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How is stoichiometry used to calculate energy released when a mass of liquid freezes?

Grams liquid × mol/g × Hfusion


If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?

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How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?

(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.


How is the Hfusion used to calculate the energy released when a mass of liquid freezes?

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How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


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