You use Heat of fusion... Heat=mass x heat of fusion
Heat of fusion for water: 80 cal/g so
35g x 80 cal/g= 2800 cal released.
The average concentration of salt in seawater is around 35 grams per liter. This means there are approximately 35 grams of salt in a liter of seawater.
The needed heat is:Q = 10 x 20 x 0,031 = 6,2 calories
6480 calories8LBs X 15 gallons x 54 DEGREES = 6480 CALORIES
(75'C)x(1g) < (75'C)x(100g) .'. The second option has more thermal energy.
heat of fusion is 333.55 (kJ/kg) rephrasing the question to the metric system: How much heat will be required to change 2.27 Kg of ice at 0 degrees into water at 27 degrees? heat of fusion is 333 * 2.27 = 756 kjoules or 756000 joules (melts the ice) specific heat of water (liquid): cp = 4.185 J/gK (this is given in grams, so we have to convert) or cp = 4185 J/kgK multiplying 4185 * 2.27 * 27 = 256,500 joules total = 256,500 + 756000 = 1012500 joules or 241,800 callories or 960 BTU
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
105C
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
Grams of what?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories are in 26 grams of carbohydrates?"
14 grams of fat has 126 calories.
There are 15 calories in 4 grams of sugar.
About 48 calories in 50 grams banana.