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How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories.
To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
What else can I help you with?
How many calories of heat needed to raise temperature of 8.1 g of water 20C?
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
If 1 gram of iron requires 0.11 calories to raise the temperature 1 degree Celsius what is iron's specific heat?
0.11cal/g degrees C
Calculate the number of calories required to raise 10.0 g of water from 25.0 to 75.0?
It takes 1 calorie to raise 1 g of water 1 degrees. Sooo... 75 - 25 = 50 degrees 50 x 10 = 500 calories or 5.00 x 10E2
How are 25000 calories of heat were used to raise rhe temperature of 400g of water to 82.5C what was the initial temp of the water?
Normally, ambient.
How many degrees will J raise the temperature of g of water?
To determine how many degrees J will raise the temperature of g of water, we need to use the specific heat capacity formula: ( Q = mc\Delta T ), where ( Q ) is the heat added (in joules), ( m ) is the mass of the water (in grams), ( c ) is the specific heat capacity of water (approximately 4.18 J/g°C), and ( \Delta T ) is the change in temperature (in °C). Rearranging the formula gives ( \Delta T = \frac{Q}{mc} ). Without specific values for Q and g, we cannot calculate the exact change in temperature.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
Is temperature measured in calories?
No, temperature is not measured in calories. Temperature is typically measured in degrees Celsius (°C) or degrees Fahrenheit (°F), while calories are units of energy related to the amount of heat required to raise the temperature of one gram of water by one degree Celsius.
How many calories are required to raise the temperature of 1 g of water by 5 degrees C?
It takes 1 calorie to raise the temperature of 1 gram of water by 1 degree Celsius. Therefore, to raise the temperature of 1 gram of water by 5 degrees Celsius, it would require 5 calories.
How many calories are needed to raise the temperature of 10 g of water from 25 C to 35 C?
100 calories. 1 calorie is defined as the amount of energy required to raise the temperature of 1 gram of 1 by 1 degree Celsius. So, if you need to raise 10 grams of water 1 degree, you would need 10 calories of energy. If you needed to raise those same 10 gram by 10 degrees, you'll need 10 * 10, or 100 calories.
How many calories are required to raise 8 grams of water 7 degrees Celsius?
The amount of heat needed to raise the temperature of a substance is given by the formula: Q = mcΔT, where Q is the heat (in calories), m is the mass (in grams), c is the specific heat capacity of water (1 cal/g°C), and ΔT is the change in temperature. Plugging in the values: Q = 8g * 1 cal/g°C * 7°C = 56 calories.
How many calories of heat needed to raise temperature of 8.1 g of water 20C?
1 calorie is defined as the amount of energy needed to raise the temperature of 1 gram of water by 1C, so... It takes 8.1 calories to raise your 8.1 grams by 1C, but you need to raise it 20C. 8.1*20=162. 162 calories is the answer you are looking for.
How much heat energy is required to change a block of ice with a mass of 55.6 grams at -11.9 degrees Celsius to steam at 123 degree Celsius?
For one gram of ice, it takes 11.9 calories to change the temperature to 0°, 80 calories to melt the ice, 100 calories to raise the water temperature to 100°, 540 calories to change the water to steam, and 23 calories to raise the steam temperature to 123°. That's a total of (11.9 + 80 + 100 + 540 + 23) calories or 754.9 calories. So to do the same to 55.6 grams of ice requires 55.6 times as much heat. 754.9 calories times 55.6 equals approximately 41972 calories (about 42 kilocalories).
If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
What is the total number of calories of heat needed to raise to raise the temperature of the liquid water from 20 degrees Celsius to 30 degrees Celsius?
To calculate the total number of calories of heat needed, you can use the formula: Q = m * c * ΔT, where Q is the heat energy in calories, m is the mass of the water, c is the specific heat capacity of water (1 calorie/gram °C), and ΔT is the change in temperature. Assuming you have 100 grams of water, the calculation would be: Q = 100g * 1 cal/g°C * 10°C = 1000 calories.
How many SI calories does it take to raise one liter if water 6 degrees Celsius?
It takes 6 SI calories to raise one liter of water by 6 degrees Celsius.
