0
What else can I help you with?
How many calories are needed to convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius?
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
How many grams of water vapor are required to saturate a kilogram of air at a temperature of -20 degrees Celsius?
At -20 degrees Celsius, the saturation vapor pressure of water is about 2.2 millibars. Therefore, to saturate a kilogram of air at this temperature, you would need about 2.2 grams of water vapor.
What is the solubility of ammonium chloride at 60 degrees Celsius?
The solubility of ammonium chloride at 60 degrees Celsius is approximately 39.2 grams per 100 grams of water.
What is the solubilty of potassium chloride at 25 degrees Celsius?
The solubility of potassium chloride at 25 degrees Celsius is approximately 34 grams per 100 grams of water.
How many grams of sodium chloride can be dissolved in 100 grams of water at 95 celsius?
Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
How many calories would be needed to melt 10 grams of ice at 0 degrees C?
To melt 10 grams of ice at 0 degrees Celsius, it would require 80 calories of heat energy per gram, so a total of 800 calories (80 calories/gram * 10 grams = 800 calories) would be needed.
How many calories are needed to convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius?
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
How much heat is required to vaporize 10 pound ice?
If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams Q = 80(4540) + 1(100 - 0)(4540) + 540(4540) Q = 720(4540) = 3,268,800 calories
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?
Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------
How much energy is required to raise 21kg of water by 2 degrees Celsius?
The specific heat capacity of water is 4.18 J/g°C. To calculate the energy required to raise 21 kg of water by 2 degrees Celsius, use the formula: Energy = mass x specific heat capacity x temperature change. Plugging in the values, the energy required is 21,084 Joules.
60 grams of ice will require how many calories to raise th temperature to one degrees Celsius?
A Calorie is defined as the amount energy required to raise 1 gram of water by 1 degree Celsius. 79.7cal are required to a phase change in 1 gram of ice to water. It is being assumed that the temperature of the ice is going to be 0 degrees Celsius, and not any colder. IE, the temperature of the water after its phase change to ice. So, since we have 60 grams of water, it will take (60*79.7) 4782cal just to complete the phase change of ice to water (cause the water to melt). If the ice measured 0 deg. Celsius, it still measures 0 deg. Celsius at this point. Now lets raise it by 1 deg. C. 60 Grams of water * 1 cal/degree C rise = 60 calories are required to raise 60 grams of water by 1 deg. C. 4782cal + 60cal = 4842 calories total to cause 60 grams of ice to phase change into water AND cause the water temperature to rise by 1 degree Celsius.
