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How many calories are required to raise 8 grams of water 7 degrees Celsius?
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∙ 11y ago
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∙ 11y ago
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How much heat is required to raise the temperature of 3.5 grams of water from 12 degrees Celsius to 35 degrees Celsius answer in calories?
80.5 calories 35-12=23 23*3.5=80.5 1c raises 1 gr. h2o 1degree centigrade Here is the formula, it should help a lot:Total Number of Calories = (Specific Heat of Water) ×(Mass of Water) × (Absolute Temperature Change)
How many grams of water can air hold at 25 degrees Celsius?
The answer depends on the quantity of air.
What is the melting point of biphenyl?
the melting point of biphenyl is 70 degrees Celsius.
What is the formula of salt that dissolved in 100 grams of water produces a solution that freezes at negative 1.40 degrees celsius with a mass of 3.9 grams?
Na3Cl2
At 20 degrees celsius grams of water can dissolve 72 grams of HCI at this point in terms os solubility the solution is said to be?
17. C} saturated
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How much energy is required to raise 21kg of water by 2 degrees Celsius?
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
How much heat is required to raise the temperature of 250 grams of water from 10 degrees to 85 degrees celsius?
q=mass * Cs * delta T = 0.25kg * 4.18 * (85-10) =78J
How much heat is required to raise the temperature of 3.5 grams of water from 12 degrees Celsius to 35 degrees Celsius answer in calories?
80.5 calories 35-12=23 23*3.5=80.5 1c raises 1 gr. h2o 1degree centigrade Here is the formula, it should help a lot:Total Number of Calories = (Specific Heat of Water) ×(Mass of Water) × (Absolute Temperature Change)
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How much heat is required to vaporize 10 pound ice?
If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams Q = 80(4540) + 1(100 - 0)(4540) + 540(4540) Q = 720(4540) = 3,268,800 calories
If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?
Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------
60 grams of ice will require how many calories to raise th temperature to one degrees Celsius?
A Calorie is defined as the amount energy required to raise 1 gram of water by 1 degree Celsius. 79.7cal are required to a phase change in 1 gram of ice to water. It is being assumed that the temperature of the ice is going to be 0 degrees Celsius, and not any colder. IE, the temperature of the water after its phase change to ice. So, since we have 60 grams of water, it will take (60*79.7) 4782cal just to complete the phase change of ice to water (cause the water to melt). If the ice measured 0 deg. Celsius, it still measures 0 deg. Celsius at this point. Now lets raise it by 1 deg. C. 60 Grams of water * 1 cal/degree C rise = 60 calories are required to raise 60 grams of water by 1 deg. C. 4782cal + 60cal = 4842 calories total to cause 60 grams of ice to phase change into water AND cause the water temperature to rise by 1 degree Celsius.
