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How many calories does it take to heat 10 grams of ice to 78 degrees C?
Wiki User
∙ 6y ago
First, you need to melt the ice. Look up the heat of fusion of ice, and multiply that by the amount of grams.Then you need to heat the water, from zero degrees to 78 degrees. Look up the specific heat of water, and then multiply together all of the following: The specific heat; the mass; the temperature difference.
Finally, add the two together.
Wiki User
∙ 6y ago
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How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
103 calories. The heat of fusion of water is 80 cal/g and it takes one calorie to change the temperature of 1 g of water by 1 degree. 80+23=103 calories
How many calories are required to heat 37.4g of lead from 15 to 60 degrees Celsius?
This heat is 51, 33 cal.
How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?
For water, the heat of fusion is 80 cal/g. So in other words, this is how many calories are needed to melt 1 gram of water that is frozen. Conversely, when you freeze 1 gram of water, you remove 80 calories of heat from it.... So, you multiply the calories needed to unfreeze a gram of water by the number of grams you have. In this case, 80 * 25 = 2000 Calories
How many calories are in a food that contains 20 grams of carbohydrate 8 grams protein and 5 grams of fat?
232
How many calories of heat are required to heat 93.6 g of methanol from -35 degrees C to 55 degrees C?
q = mass * specific heat * change in temp. ( Joules, so conversion at end ) q = (93.6 g)(2.51 J/gC)[55o C - ( - 35o C)] = 21144.24 Joules ===============================
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?
1370 calories
How many joules of heat energy must be supplied to 21 g of water to raise the temperature of the water from 24 to 95 degrees Celsius?
21 grams through 71 degrees is 21x71 calories.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How many calories to heat 10 ml of water from 25 degrees to 35 degrees C?
100
How many calories are required to raise 8 grams of water 7 degrees Celsius?
700
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
103 calories. The heat of fusion of water is 80 cal/g and it takes one calorie to change the temperature of 1 g of water by 1 degree. 80+23=103 calories
How many calories are released when 35 grams of water at 0 degrees freezes?
You use Heat of fusion... Heat=mass x heat of fusion Heat of fusion for water: 80 cal/g so 35g x 80 cal/g= 2800 cal released.
How many calories are required to heat 37.4g of lead from 15 to 60 degrees Celsius?
This heat is 51, 33 cal.
