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80.5 calories  35-12=23   23*3.5=80.5 1c raises 1 gr. h2o 1degree centigrade

Here is the formula, it should help a lot:Total Number of Calories = (Specific Heat of Water) ×(Mass of Water) × (Absolute Temperature Change)
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Q: How much heat is required to raise the temperature of 3.5 grams of water from 12 degrees Celsius to 35 degrees Celsius answer in calories?
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