80.5 calories 35-12=23 23*3.5=80.5 1c raises 1 gr. h2o 1degree centigrade
Here is the formula, it should help a lot:Total Number of Calories = (Specific Heat of Water) ×(Mass of Water) × (Absolute Temperature Change)700
25 degrees Celsius.
A temperature of 91 degrees Fahrenheit is equal to a temperature of 32.78 degrees Celsius.
It takes 80 calories per gram to increase the temperature of water by one degree. 4000 * 80 * 100 = 32000000 calories.
500 degrees Celsius
The number of calories required will depend on the mass of water which is to be heated.
100 degrees Celsius
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
Cloud formation does not require the air temperature to be at zero degrees Celsius.
700
3.50 J
115.2
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
1935 J (apex)
105C
Zero degrees Celsius.