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You have 6 different positions to fill with the letters {A, B, S, E, N, T} without repeating any letter.
For you first position, you can pick any letter from the group. You have 6 different possibilities. For the second position, you can pick, any of the 5 remaining letters ( 5 possibilities). So far you have 30 possible combinations ( 6 x 5 ). for the third position you have 4 remaining letters. If you follow this logic, the end result is:
6 x 5 x 4 x 3 x 2 x 1 = 720
This can be shortened to factorial nomenclature.
6! = 720
Cheers!
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