0
What else can I help you with?
How many permutations are there in a 3-letter code which can use the letters from A to Z inclusive?
A - Z means you can use the whole alphabet, which usually contains 26 letters. So a one-letter code would give you 26 permutations. 2 letters will give you 26 x 26 permutations. A three letter code, finally, will give you 26 x 26 x 26 , provided you don't have any restrictions given, like avoiding codes formed from 3 similar letters and such.
How many different 4-letter words can be formed using the letters of the word NATION?
8 different 4-letter words can be formed from the letters of the word "Nation".
How many different nine letter arrangements can be formed from the nine letters of the word logarithm?
Algorithm is the only nine letter word.
What 9 letter word will be formed using letters BRAIN?
Librarian is a 9 letter word that has letters BRAIN in it.
What seven letter word can be formed using the letters mcuanst?
The seven letters, mcuanst, can be formed into the seven letter word, sanctum. Sanctum is an English word meaning 'a sacred place.'
How many different 3 letter permutations can be formed from the letters in the word count?
There are 5*4*3 = 60 permutations.
How many different three letter permutations can be formed from the letters in the word clipboard?
There are three that I can see, there's clip, board and lip.
How may different nine-letter permutations can be formed from the nine letters in the word isosceles?
9*8*7 / 2! / 3!
How many different three letter permutations can be from the letter in the word clipboard?
There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many different 4-letter permutations can be formed from the letters in the word DECAGON?
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
How many 5 letter permutations can be formed from the letters in vertical?
There are 8P5 = 8*7*6*5*4 = 6720
How many Five letter word using letters a a g m m r?
To find the number of five-letter words that can be formed using the letters a, a, g, m, and m, we can use the formula for permutations of multiset. The total permutations of the letters is given by ( \frac{5!}{2! \times 2!} = \frac{120}{4} = 30 ). Therefore, there are 30 distinct five-letter arrangements that can be formed with the given letters.
What is the number of distinguishable permutations of the letters in the word oregon?
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
How many different 7 letters permutations can be formed from 5 identical H's and two identical T's?
To find the number of different 7-letter permutations that can be formed from 5 identical H's and 2 identical T's, we use the formula for permutations of multiset: [ \frac{n!}{n_1! \times n_2!} ] where (n) is the total number of letters, and (n_1) and (n_2) are the counts of each type of letter. Here, (n = 7), (n_1 = 5) (for H's), and (n_2 = 2) (for T's). Thus, the calculation is: [ \frac{7!}{5! \times 2!} = \frac{5040}{120 \times 2} = \frac{5040}{240} = 21 ] Therefore, there are 21 different permutations.
How many different ways are there to to scramble to letters of the word mass if s needs to be the first letter?
The number of permutations of the letters MASS where S needs to be the first letter is the same as the number of permutations of the letters MAS, which is 3 factorial, or 6. SMAS SMSA SAMS SASM SSMA SSAM
