58.1g [Ca(PO4)] X
1 mol [Ca(PO4)] X
2 mol (PO4) X
1 mol (P) X
30.97g (P)
= 11.6g (P)
310.2g [Ca(PO4)]
1 mol[Ca(PO4)]
1 mol (PO4)
1 mol (P)
Sorry about the formatting, im trying to show stoichiometry.
Calcium is a 2+ while phosphate is a 3- . To balance them you would need 3 calcium and 2 phosphate. Giving a formula of: Ca3(PO4)2 Therefore: 3 Ca + 2 P + 8 O = 13 atoms
Technicly a compound is formed from many elements. Phosphorus is an element and cant be broken down into other elements (its number 15 on the perdiodic table) it does however form many compounds when it bonds to other elements : calcium phosphate, magnesium phosphate and phosphoric acid are just a few.
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
A phosphate ion (PO4) contains 4 oxygen atoms, 1 phosphorus atom, and a total of 3 phosphate atoms.
To calculate the liters of water needed, first convert 1 gram of calcium phosphate into moles. Then, use the molar mass of calcium phosphate to convert moles into grams. Next, apply the solubility value to calculate the amount of calcium phosphate that can dissolve in 1 liter of water. This will give you the approximate amount of water needed to dissolve 1 gram of calcium phosphate.
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
Calcium is a 2+ while phosphate is a 3- . To balance them you would need 3 calcium and 2 phosphate. Giving a formula of: Ca3(PO4)2 Therefore: 3 Ca + 2 P + 8 O = 13 atoms
Technicly a compound is formed from many elements. Phosphorus is an element and cant be broken down into other elements (its number 15 on the perdiodic table) it does however form many compounds when it bonds to other elements : calcium phosphate, magnesium phosphate and phosphoric acid are just a few.
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
There are approximately 6.022 x 10^22 phosphorus atoms in 1.0 gram of phosphorus, based on Avogadro's number.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
A phosphate ion (PO4) contains 4 oxygen atoms, 1 phosphorus atom, and a total of 3 phosphate atoms.
Phosphorus is a chemical element, while phosphatase is an enzyme used to remove chemical groups containing phosphorus, called phosphate gr oups, which are present in many bio molecules.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
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