58.1g [Ca(PO4)] X
1 mol [Ca(PO4)] X
2 mol (PO4) X
1 mol (P) X
30.97g (P)
= 11.6g (P)
310.2g [Ca(PO4)]
1 mol[Ca(PO4)]
1 mol (PO4)
1 mol (P)
Sorry about the formatting, im trying to show stoichiometry.
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Calcium phosphate has the chemical formula Ca3(PO4)2. The molar mass of calcium phosphate is 310.18 g/mol. The molar ratio of phosphorus to calcium phosphate is 2:1, so there are 31.0 grams of phosphorus in 58.1 grams of calcium phosphate.
Calcium is a 2+ while phosphate is a 3- . To balance them you would need 3 calcium and 2 phosphate. Giving a formula of: Ca3(PO4)2 Therefore: 3 Ca + 2 P + 8 O = 13 atoms
Phosphorus in its elemental form combines with oxygen to form various phosphorus oxides, such as phosphorus pentoxide (P2O5) and phosphorus trioxide (P4O6). These compounds are produced through the combustion of phosphorus in the presence of oxygen.
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
A phosphate ion (PO4) contains 4 oxygen atoms, 1 phosphorus atom, and a total of 3 phosphate atoms.