0
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample.
(mass of sample) x (mass of phosphorus/total mass)
Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes:
500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g
molar mass of phosphorus: 30.97 g/mol
molar mass of calcium phosphate: 310.17 g/mol
total mass: 500 g
Still curious? Ask our experts.
Chat with our AI personalities
Blake
Devin
Lao
Add your answer:
Earn +20 pts
How many grams of nitrogen and phosphorus are available in 1.00 pound of ammonium phosphate?
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
How many grams are in 2.3x10-4 moles of calcium phosphate?
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
How many grams of calcium phosphate are theoretically produced if you start with 10.3 moles of CaNO32 and 7.6 moles of Li3PO4?
735 g of Ca3(PO4)2 are obtained.
How many grams are in 120 grams of calcium?
120
How many grams in a tablespoon of calcium?
There are approximately 1.37 grams of calcium in one tablespoon of calcium citrate powder.
