The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample.
(mass of sample) x (mass of phosphorus/total mass)
Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes:
500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g
molar mass of phosphorus: 30.97 g/mol
molar mass of calcium phosphate: 310.17 g/mol
total mass: 500 g
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
735 g of Ca3(PO4)2 are obtained.
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58.1g [Ca(PO4)] X 1 mol [Ca(PO4)] X 2 mol (PO4) X 1 mol (P) X 30.97g (P) = 11.6g (P) 310.2g [Ca(PO4)] 1 mol[Ca(PO4)] 1 mol (PO4) 1 mol (P) Sorry about the formatting, im trying to show stoichiometry.
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the grams of phosphorus in calcium phosphide, first find the molar mass of calcium phosphide (Ca3P2 = 3Ca + 2P = 340.08 + 230.97 = 276.42 g/mol), then calculate the mass percent of phosphorus in calcium phosphide (2P/276.42 g/mol * 100%). Finally, determine the grams of phosphorus in 500 grams of calcium phosphide by multiplying the mass percent by 500 grams.
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
Calcium is a 2+ while phosphate is a 3- . To balance them you would need 3 calcium and 2 phosphate. Giving a formula of: Ca3(PO4)2 Therefore: 3 Ca + 2 P + 8 O = 13 atoms
The daily requirement of phosphorus is 800. How many grams of phosphorus are needed?
Technicly a compound is formed from many elements. Phosphorus is an element and cant be broken down into other elements (its number 15 on the perdiodic table) it does however form many compounds when it bonds to other elements : calcium phosphate, magnesium phosphate and phosphoric acid are just a few.
42,5 grams calcium is equivalent to 1,06 moles.
To calculate the liters of water needed, first convert 1 gram of calcium phosphate into moles. Then, use the molar mass of calcium phosphate to convert moles into grams. Next, apply the solubility value to calculate the amount of calcium phosphate that can dissolve in 1 liter of water. This will give you the approximate amount of water needed to dissolve 1 gram of calcium phosphate.
There are 4 phosphorus atoms in one molecule of copper phosphate (Cu3(PO4)2). Therefore, in 7.6 moles of copper phosphate, there would be 7.6 moles x 4 atoms = 30.4 moles of phosphorus atoms.
735 g of Ca3(PO4)2 are obtained.