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The B,C,D,K,Z indicates the instantaenous tripping current. It means the minimum value of current causes the circuit to trip without intentional time delay. approximately < 100ms. Consider Rated Current be : (In) Instantaenous tripping current for C Curve is 5-10 times the rated current(In). Instantaenous tripping current for D Curve is 10-20 times the rated current(In).
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What is the distance between the z-intercept from the x intercept in the equation ax plus by plus cz plus d equals 0?
ax + by + cz + d = 0At the z-intercept, 'x' and 'y' are both zero.cz + d = 0 --> z = -d/c --> The z-intercept is the point (0, 0, -d/c).At the x-intercept, 'y' and 'z' are zero.ax + d = 0 --> x = -d/a --> The x-intercept is the point (-d/a, 0, 0).The distance between the points (0, 0, -d/c) and (-d/a, 0, 0) issqrt[ (-d/a)2 + (-d/c)2 ] = sqrt (d2/a2 + d2/c2) = d sqrt(1/a2 + 1/c2)
Solve each formaul for the indicated variable d equals rt for t?
d = r t t = d / r
How do you Factor 12bc - 4bd - 15xc plus 5xd?
12bc - 4bd - 15xc + 5xd = 4b(3c - d) - 5x(3c - d) = (3c - d)(4b - 5x)
What is the maximal of nodes in binary tree of depth D?
2^(d+1) - 1
What is the derivative of secxtanx?
d/dx(uv)=u*dv/dx+v*du/dxd/dx(secxtanx)=secx*[d/dx(tanx)]+tanx*[d/dx(secx)]-The derivative of tanx is:d/dx(tan u)=[sec(u)]2*d/dx(u)d/dx(tan x)=[sec(x)]2*d/dx(x)d/dx(tan x)=[sec(x)]2*(1)d/dx(tan x)=(sec(x))2=sec2(x)-The derivative of secx is:d/dx(sec u)=[sec(u)tan(u)]*d/dx(u)d/dx(sec x)=[sec(x)tan(x)]*d/dx(x)d/dx(sec x)=[sec(x)tan(x)]*(1)d/dx(sec x)=sec(x)tan(x)d/dx(secxtanx)=secx*[sec2(x)]+tanx*[sec(x)tan(x)]d/dx(secxtanx)=sec3(x)+sec(x)tan2(x)
