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Factors include the angle at which it is fired, the speed of the projectile, its shape (ballistic coefficient) the air pressure and humidity.
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Which factor has a significant impact on a firearms' maximum projectile range?
Weight, velocity, and shape of the bullet.
Which factor has a significant impact on a firearm maximum projectile range?
velocity
Which factor has a significant impact on a firearm's maximum projectile range?
velocity
What factors have a significant impact on a firearms maximum projectile range?
Speed, weight, and shape of the projectile- along with the angle at which the barrel is raised above the horizonatal.
The range of projectile is maximum when the angle of projection is?
The range of projectile is maximum when the angle of projection is 45 Degrees.
At what launch angle or angles will the projectile land at half of its maximum possible range?
The half maximum range of a projectile is launched at an angle of 15 degree
Under what conditions will a projectile travel maximum range?
Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.
What is the Distance of 22 short?
Are you asking about the maximum effective range or the maximum range that a 22 short projectile can travel?
What is the only factor that affects the range of a projectile?
Gravity
What factor affects a firearm's maximum projectile range?
The weight and shape of the bullet, the speed at which the bullet leaves the gun, and the degree of tilt of the barrel above the horizontal.
How many the range of projectile is maximum when it is projected at an angle?
At 45° angle.
What is maximum rang of projectile motion?
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
