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Speed, weight, and shape of the projectile- along with the angle at which the barrel is raised above the horizonatal.

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Q: What factors have a significant impact on a firearms maximum projectile range?
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Which factor has a significant impact on a firearms' maximum projectile range?

Weight, velocity, and shape of the bullet.


What is a factor on a firearms maximum projectile range?

Factors include the angle at which it is fired, the speed of the projectile, its shape (ballistic coefficient) the air pressure and humidity.


Which factor has a significant impact on a firearm maximum projectile range?

velocity


Which factor has a significant impact on a firearm's maximum projectile range?

velocity


The range of projectile is maximum when the angle of projection is?

The range of projectile is maximum when the angle of projection is 45 Degrees.


What factor has a significant impact on a firearm's range?

The first factors are: Speed, weight, and shape of the projectile. Speed will be determined by the powder charge used to drive the bullet, and the length of the barrel. Elevation angle (the angle at which the barrel points upward) will then increase or decrease the range based on the first three factors. For most firearms the optimal elevation angle is between 30 and 40 degrees for maximum range. Other lesser factors include the weather (wind, humidity, temperature) and altitude. Even the Coriolis Effect can play a small factor.


At what launch angle or angles will the projectile land at half of its maximum possible range?

The half maximum range of a projectile is launched at an angle of 15 degree


Under what conditions will a projectile travel maximum range?

Ignoring the effects of wind and air-resistance in general, maximum projectile range results when the projectile is launched/fired in a direction 45 degrees above the horizontal.


What is maximum momentum and minimum momentum in projectile motion?

You are wrong


What is maximum rang of projectile motion?

Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.


What is the magnitude of the velocity of a vertical projectile at its maximum height is equal to?

The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.


How many the range of projectile is maximum when it is projected at an angle?

At 45° angle.