No, THC is a cannabinoid, there are no cannabinoids in spice. It wont show up on a cannabis drug test.
If I'm not mistaking, Spice is legal, The main ingredient that gets you high, is not THC. So you should pass. but honestly, If you where smart you wouldn't smoke any drugs...
Spice uses "cannaboids" which are synthetic forms of THC that are created in labs. Some states have made the cannaboids used in spice illegal, however, spice does not show up on drug tests. There is no detox period because there is no way to test for those cannaboids. I'm in the military, and have smoked spice multiple times the night before two or three different drug test. So no worries, you're good. :)
THC is not an acid.
cigarette filters remove the THC.
You can get THC in your body by consuming marijuana.
No there is no THC in spice. Spices is sprayed with a synthetic compound chemically similar to THC but it will not come up in a drug test.
No. Spice is a mixture of random dangerous chemicals. Spice kills allot of people, THC has never killed anyone in history.
Spice contains cannabicyclohexanol, which is "synthetic" thc, whereas weed has THC (tetrahydrocannibinol) and cannabinoid
Yes spice does contain THC in it, and if consumed will make you turn in a positive test for THC.
no
I hope NOT!
No sir :D
Yes, and it is very high in THC. people have died from spice.
Yes and no. Spice is a cannabanoid with a compleatly different actor ingrediant called JHW-018, which had a different structure then THC will not show up on a THC test. However since it is a cannanbinoid, some type of spice contain small about of THC, but it will only show up as so for a few hours after use. Be warned though, it is on it's way to becoming illegal, and certain labs are able to test for JWH-018z.
yes because of thc cells
No it won't because there is no thc they test for thc because I just got a ya today and I'm clean
If by synthetic marijuana you mean Spice, then you Dont need to detox. There is no THC in Spice and plus it filters out of your system in about 2days.