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26x10^-6/ 314= 8.3*10^-8 moles

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To determine the number of moles of THC in 26 μg, we first need to calculate the molar mass of THC which is approximately 314.47 g/mol. Then, we divide the given mass (26 μg or 0.000026 g) by the molar mass to find the moles. This gives us approximately 8.3 x 10^-8 moles of THC.

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Q: How many moles of THC does this 26 ug represent?
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How many molecules of THC does this 26 ug represent?

To determine the number of THC molecules in 26 µg, you first need to convert the mass of THC to moles using its molar mass. Then, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules. This calculation will give you the number of THC molecules in 26 µg.


What number of moles does 32.00 g of LiF represent?

To find the number of moles in 32.00 g of LiF, you first need to calculate the molar mass of LiF, which is 25.94 g/mol for Li and 19.00 g/mol for F. Adding these together gives a molar mass of 25.94 + 19.00 = 44.94 g/mol for LiF. Then, divide the given mass by the molar mass: 32.00 g / 44.94 g/mol = 0.71 moles of LiF.


How many moles are represented by 4.70 x 1026 atoms of uranium?

To determine the number of moles, first calculate the number of moles in one mole of uranium using Avogadro's number (6.022 x 10^23 atoms/mol). Then, divide the given number of atoms by the number of atoms per mole to find that 4.70 x 10^26 atoms of uranium represents 7.81 moles.


How many moles of aluminum are present in 856g of aluminum sample?

To determine the number of moles of aluminum present in 856g, you need to divide the mass by the molar mass of aluminum. The molar mass of aluminum is approximately 26.98 g/mol. So, 856g ÷ 26.98 g/mol ≈ 31.7 moles of aluminum are present in 856g.


What is the mass of CO2 and H2O produced after combusting 100 g of acetylene?

The balanced chemical equation for the combustion of acetylene (C2H2) is 2C2H2 + 5O2 -> 4CO2 + 2H2O. From the equation, for every 2 moles of acetylene combusted, 4 moles of CO2 and 2 moles of H2O are produced. Since the molar mass of acetylene is 26 g/mol, 100 g of acetylene is equivalent to 100/26 = 3.85 moles. Therefore, 3.85 moles of acetylene combustion would produce 7.7 moles of CO2 and 3.85 moles of H2O.