Wiki User
∙ 8y agoThe pressure is approx. 2 atmospheres.
Wiki User
∙ 8y agoWiki User
∙ 8y agoPV = nRT
P = nRT/V = (4)(0.0821)(308)/50 = 2.02 atm = 2 atm (1 sig fig)
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
2.02 atm
The pressure is 2,02 atmospheres.
2.02atm
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
The pressure will be 2,02 atmospheres.
2.02 atm
The pressure is 2,02 atmospheres.
Using the ideal gas law equation PV = nRT, we can rearrange it to solve for pressure (P). Substituting the values given: n = 4 moles, V = 50 L, T = 308 K, and R = 0.0821 L.atm/(mol.K), we can calculate the pressure of helium in the tank. P = (4 moles)(0.0821 L.atm/(mol.K))(308 K)/(50 L). Therefore, the pressure of 4 moles of helium in a 50 L tank at 308 K is approximately 2.5 atm.
2.02 atm
2.02 atm (apex)
We can use the equation PV=nRT. There are 2.048#10^5 pascels.
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