Wiki User
∙ 11y ago2.02atm
Wiki User
∙ 11y agoAnonymous
Anonymous
Kkakalilb
The pressure of the helium can be calculated using the ideal gas law: PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature in Kelvin. P = nRT/V. Plugging in the values, P = (4 moles)(0.0821 L.atm/mol.K)(308 K)/(50 L) = 2.54 atm. Thus, the pressure of 4 moles of helium in a 50 L tank at 308 K is 2.54 atm.
Using the ideal gas law (PV = nRT), where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature in Kelvin, we can solve for pressure. Plugging in the values, the pressure of the 4 moles of helium in a 50 liter tank at 308 K is approximately 81.6 atm.
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
2.02 atm
Using the ideal gas law (PV = nRT), where P is pressure, V is volume, n is number of moles, R is the ideal gas constant, and T is temperature in Kelvin, we can solve for pressure. Plugging in the values, the pressure of the 4 moles of helium in a 50 liter tank at 308 K is approximately 81.6 atm.
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
2.02 atm
The pressure will be 2,02 atmospheres.
The pressure is 2,02 atmospheres.
2.02 atm
2.02 atm
Using the ideal gas law equation PV = nRT, we can rearrange it to solve for pressure (P). Substituting the values given: n = 4 moles, V = 50 L, T = 308 K, and R = 0.0821 L.atm/(mol.K), we can calculate the pressure of helium in the tank. P = (4 moles)(0.0821 L.atm/(mol.K))(308 K)/(50 L). Therefore, the pressure of 4 moles of helium in a 50 L tank at 308 K is approximately 2.5 atm.
2.02 atm (apex)
We can use the equation PV=nRT. There are 2.048#10^5 pascels.