Carbon Tetrabromide
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∙ 12y agoCBr4 is carbon tetrabromide, a chemical compound consisting of one carbon atom bonded to four bromine atoms. It is a colorless, crystalline solid at room temperature and is primarily used in organic synthesis and as a reagent in chemical reactions.
CBr4 , this is the correct formula for carbon-tetra-bromide
1
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
CBr4
The formula for carbon terabromide is CBr4. It consists of one carbon atom and four bromine atoms.
CBr4 , this is the correct formula for carbon-tetra-bromide
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Yes
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
CBr4
Carbon and bromine can combine to form carbon tetrabromide. Its chemical formula is CBr4.
Carbon Tetrabromide - or tetrabromomethane
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Tetrahedral
The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
No, tetrabromomethane (CBr4) is a covalent compound, not ionic. It is composed of nonmetal elements (carbon and bromine) that share electrons to form covalent bonds.
Tetrabromomethane (CBr4) is a compound.