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What is CBr4 in chemistry?

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∙ 13y ago

Updated: 6/15/2024

Carbon Tetrabromide

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∙ 13y ago

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What is the symbol for CBr4?

CBr4 , this is the correct formula for carbon-tetra-bromide

How many carbon atoms are in CBr4?

1

How many molecules are in 393g of CBr4?

The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23

What compound do you expect to be miscible with octane (C8H18)?

CBr4

What is the formula for carbon terabromide?

The formula for carbon terabromide is CBr4. It consists of one carbon atom and four bromine atoms.

Related Questions

What is the symbol for CBr4?

CBr4 , this is the correct formula for carbon-tetra-bromide

Will CBr4 and H2O form homogeneous solutions when combined?

No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.

Is CBr4 metal or non-metal?

Yes

Formula for carbon tetrabromide?

CBr4

How many molecules are in 325g of CBr4?

To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.

What compound does carbon and bromine create and what is its chemical formula?

Carbon and bromine can combine to form carbon tetrabromide. Its chemical formula is CBr4.

How many carbon atoms are in CBr4?

1

What is the molecular geometry shape of CBr4?

Tetrahedral

What is the name for CBr4?

Carbon Tetrabromide - or tetrabromomethane

How many molecules are in 393g of CBr4?

The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol This means that a 393g pure sample contains 1.19 moles of tetrabromomethane. The Avogadro's number is 6.02 x 10^23 So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23

Is tetrabromomethane a compound or a mixture?

Tetrabromomethane (CBr4) is a compound.

What compound do you expect to be miscible with octane (C8H18)?

CBr4

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