The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol
This means that a 393g pure sample contains 1.19 moles of tetrabromomethane.
The Avogadro's number is 6.02 x 10^23
So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
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CBr4 , this is the correct formula for carbon-tetra-bromide
Carbon tetrabromide (CBr4) contains a total of 36 electrons. Each carbon atom contributes 4 electrons, while each bromine atom contributes 7 electrons. There are 4 bromine atoms in CBr4, totaling 28 electrons, along with the 8 electrons contributed by the 2 carbon atoms.
CBr4
The formula for carbon terabromide is CBr4. It consists of one carbon atom and four bromine atoms.