The molecular mass of CBr4 is 12.0 + 4(79.9) = 331.6Amount of CBr4 = mass of substance / molecular mass = 393/331.6 = 1.19mol
This means that a 393g pure sample contains 1.19 moles of tetrabromomethane.
The Avogadro's number is 6.02 x 10^23
So, number of molecules of CBr4 = 1.19 x 6.02 x 10^23 = 7.13 x 10^23
1
CBr4 , this is the correct formula for carbon-tetra-bromide
Carbon tetrabromide (CBr4) contains a total of 36 electrons. Each carbon atom contributes 4 electrons, while each bromine atom contributes 7 electrons. There are 4 bromine atoms in CBr4, totaling 28 electrons, along with the 8 electrons contributed by the 2 carbon atoms.
CBr4
The formula for carbon terabromide is CBr4. It consists of one carbon atom and four bromine atoms.
To find the number of molecules in 325g of CBr4, first calculate the number of moles using the molar mass of CBr4 (331.63 g/mol). Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. So, 325g of CBr4 is equal to about 0.981 moles, which is approximately 5.91 x 10^23 molecules.
To calculate the number of molecules in 334 g of CBr4, you need to first convert the mass to moles using the molar mass of CBr4 (331.6 g/mol). Once you have the moles, you can then use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules in 334 g of CBr4.
To find the number of molecules in 366g of CBr4, first calculate the molar mass of CBr4 which is 331.63 g/mol. Next, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert grams to molecules. Divide the given mass by the molar mass and then multiply by Avogadro's number to find the number of molecules.
1
CBr4 , this is the correct formula for carbon-tetra-bromide
CF4 has the lowest viscosity, followed by CCl4, and then CBr4. This is because viscosity is generally higher for heavier molecules due to stronger intermolecular forces that inhibit molecular motion.
There are four covalent bonds present in CBr4. Each carbon atom forms a single covalent bond with each of the four bromine atoms.
No, CBr4 and H2O will not form a homogeneous solution. CBr4 is a nonpolar compound, while H2O is polar. Due to the significant difference in polarity, they will not mix evenly to form a homogeneous solution.
Yes
CBr4
The intermolecular forces in carbon tetrabromide (CBr4) are primarily London dispersion forces. These are weak forces resulting from temporary fluctuations in electron distribution that induce dipoles in adjacent molecules. There are no hydrogen bonding or dipole-dipole interactions in CBr4 due to its symmetrical tetrahedral structure.
Carbon tetrabromide (CBr4) contains a total of 36 electrons. Each carbon atom contributes 4 electrons, while each bromine atom contributes 7 electrons. There are 4 bromine atoms in CBr4, totaling 28 electrons, along with the 8 electrons contributed by the 2 carbon atoms.