A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
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To prepare a 250 mM solution of sucrose, you would need to weigh out a certain amount of sucrose (table sugar) and dissolve it in a specific volume of water. The exact amount of sucrose needed will depend on its molar mass (342.3 g/mol). You can calculate the amount of sucrose required using the formula: moles = (desired concentration in mM) x (volume in L).
1 M sucrose is 342.29 g in 1 L of water
1 mM sucrose= 0.3429 g
250 mM sucrose is 0.3429 * 250 = 85.87 g in 1 L of water
if preparing 100 ml of solution
for 1000 ml----85.87g
for 100 ml-----8.578 g
N should be M, meaning number of mole (N) per litre.
Concentration equals the number of mole per litre, or simply C=N/V.
We know the concentration is 0.1 mol/L
One mole of sucrose = 342g (from the molecular formula C12H22O11)
so 0.1 mol = 34.2g.
To make a 0.1 M sucrose solution, mix 34.2 grams of sucrose into every litre of water.
molarity (M) = moles/litre of solution
To make a 1.0 M sucrose solution, you need the molar mass of sucrose. C12H22O11
(12x12.0) + (22x1.0) + (11x16.0) = (according to wikipedia 342.30 g/mole)
Take the 342.20 grams of sucrose and put it into a graduated cylinder and then fill to the 1.0 L mark with water.
For 1 M Sucrose solution, 342g sucrose will be added in distilled water to make up the final volume to 1000ml. Therefore, for 0.25 ml, exactly one fourth, i.e., 85.5 g of sucrose will be added in distilled water to make up the final volume to 1000ml. This will result in the concentration of 0.25 M.
To prepare a 10 mm solution, you would dilute the 4 M stock solution. Use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution (4 M), V1 is the volume of stock solution needed, C2 is the desired final concentration (10 mM), and V2 is the final volume of the solution. Calculate the volume of stock solution needed to achieve the desired concentration, then add solvent (usually water) to reach the final volume.
To prepare 25 mM NH4HCO3, first calculate the amount of NH4HCO3 needed based on its molecular weight. Weigh out the calculated amount of NH4HCO3 and dissolve it in the appropriate volume of water to make a 25 mM solution. Finally, adjust the final volume with water if necessary.
250 mm is equal to 0.25 meters. This conversion can be done by dividing the millimeter measurement by 1000 (since there are 1000 mm in a meter).
show solution convert 0.015 km to mm
To dilute a 100 mM solution to 5 mM, you would need to dilute it by a factor of 20. To do this, you can add 19 parts of a suitable solvent (such as water) to 1 part of the 100 mM solution. Mix thoroughly to ensure a homogeneous 5 mM solution.