How much NaCl is required for 100 mM NaCl solution?

Answer 1

To prepare a 100 mM NaCl solution, you would need to calculate the molecular weight of NaCl, which is approximately 58.44 g/mol (sodium's atomic weight is 22.99 g/mol and chlorine's is 35.45 g/mol). To make a 100 mM solution, you would need 0.1 moles of NaCl per liter of solution. This would be equivalent to 5.844 grams of NaCl per liter of solution.

Answer 2

To prepare a 100 mM NaCl solution, you would need to dissolve 5.84 grams of NaCl in water to make a final volume of 1 liter. This calculation is based on the molar mass of NaCl (58.44 g/mol) and the definition of molarity (Molarity = moles of solute / volume of solution in liters).

Answer 3

For 100 mM NaCl solution in 1L: Formula weight: 58.44 g/L Answer: 5.844 g/L if you want in 500 mL---2.922 g if you want in 250 mL---1.461 g if you want in 100 mL---584.4 mg

Answer 4

dissolve 0.745 grm kcl solutin in 100 ml distilled water

Answer 5

6 g/l de NaCl

Answer 6

The mass of NaCl is 29,22 g.

Answer 7

58 milligrams of NaCl are needed.