To find the molarity of NaCl in a saturated solution, you need to know the mass of NaCl dissolved in a given volume of solvent. Then you can calculate the moles of NaCl and divide it by the volume of the solution in liters to find the molarity. Keep in mind that in a saturated solution, some NaCl may remain undissolved.
To calculate the molarity of the solution, first convert the mass of NaCl to moles using its molar mass. Then, divide the moles of NaCl by the total volume of the solution in liters (2000 ml = 2 L) to find the molarity. In this case, the molarity would be calculated as moles of NaCl / 2 L.
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
To calculate molarity, first find the moles of the solute (NaCl) using its molar mass. The molar mass of NaCl is 58.44 g/mol (Na=22.99 g/mol, Cl=35.45 g/mol). Divide the mass of NaCl (19.55 g) by its molar mass to get moles. Then, divide the moles by the volume of solution in liters (0.25 L) to find the molarity.
The molarity of the sugar solution can be calculated using the formula: molarity = moles of solute / liters of solution. Plugging in the values, molarity = 21.0 moles / 52.0 L which equals 0.404 Molarity.
To calculate the molarity of the solution, first convert the mass of NaCl to moles using its molar mass. Then, divide the moles of NaCl by the total volume of the solution in liters (2000 ml = 2 L) to find the molarity. In this case, the molarity would be calculated as moles of NaCl / 2 L.
Find moles NaCl first.14.60 grams NaCl (1 mole NaCl/58.44 grams)= 0.2498 moles NaCl================Now,Molarity = moles of solute/Liters of solutionMolarity = 0.2498 moles NaCl/2.000 Liters= 0.1249 M NaCl solution--------------------------------
To calculate the molarity, you first need to convert the mass of NaCl to moles. The molar mass of NaCl is 58.44 g/mol. Therefore, 300 grams of NaCl is equal to 300/58.44 = 5.13 moles. Next, divide the moles of NaCl by the volume of the solution in liters (3000 L) to get the molarity, which is 5.13 moles / 3000 L = 0.00171 M.
To find the molarity, first calculate the moles of NaCl using its molar mass (58.44 g/mol). Then, divide the moles of NaCl by the volume of solution in liters (0.1 L) to get the molarity in moles per liter.
After transferring 50 grams of the 1.7 M NaCl solution to a new beaker, the final amount of NaCl in the original beaker will be 50 grams. To find the new molarity, you would first calculate the new moles of NaCl in the beaker, then divide by the total volume of the solution in liters. The molarity will be reduced in the original beaker due to the dilution from transferring a portion of the solution.
To find the molarity of the solution, first calculate the number of moles of sodium sulfate by dividing the mass (15.5g) by the molar mass of sodium sulfate (142.04 g/mol). Next, convert the volume of the solution to liters (35 ml = 0.035 L). Finally, divide the number of moles by the volume in liters to get the molarity of sodium sulfate in the solution.
To find the volume of the solution containing 0.500 g of NaCl, first, calculate the moles of NaCl using its molar mass (58.44 g/mol). Then use the molarity formula (Molarity = moles/volume) to find the volume. The volume of a 0.150 M solution that contains 0.500 g of NaCl would be approximately 8.5 ml.
To find the number of moles of sodium chloride, you can multiply the volume of the solution by its molarity. moles = volume (L) * molarity moles = 5.08 L * 2.36 mol/L moles = 11.9928 mol Therefore, there are approximately 11.99 moles of sodium chloride in 5.08 L of a 2.36 M solution.
Pretty concentrated! ( I assume you mean 2.3 Liters )First get the moles of sodium chloride.456 grams NaCl (1 mole NaCl/58.44 grams)= 7.803 moles NaCl==============Now,Molarity = moles of solute/Liters of solutionMolarity = 7.803 moles NaCl/2.3 Liters= 3.4 M NaCl solution----------------------------
To determine the amount of NaCl in the solution, you first need to calculate the moles of NaCl present. Using the given molarity (2.48 M) and the volume of the solution (assumed to be 806 g = 806 ml for water), you can find the moles of NaCl. Then, you convert the moles of NaCl to grams using the molar mass of NaCl (58.44 g/mol) to find the amount of NaCl in the solution.
The Molarity of the solution is .901
To find the volume of the solution, first calculate the moles of NaCl in 0.500 g using its molar mass. Then, use the concentration to determine the volume using the formula: moles = molarity x volume. Rearrange the formula to solve for volume, which would be moles / molarity. Substituting the moles of NaCl and the concentration into the formula will give you the volume of the solution.