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To answer this question the voltage of the immersion heater is needed. I = W/E.

Q: How many amps breaker you need for a 5000 watts immersion heater?

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1 watt RMS equals to 100PMPO , accordingly 1000watt RMS equals to 10,000 PMPO. check out LG Home Theater HB954TB for the same.

162 X 5000= 810,000

The GCF is 1.

15,000

5000 del peru

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The formula you are looking for is I = W/E, Amps = Watts/Volts. Amps = 5000/230 =21.7 amps. The wire size to run this heater would be a #10 copper conductor. The supply breaker would be a two pole 30 amp breaker.

Yes, you can but the wattage output rating of the heater will not be reached due to the lower applied voltage. For example if the heater is 5000 watts at 277 volts, the current is I = W/E 5000/277 = 18 amps. The resistance of the heater is R = W/I (squared) = 5000/18 x 18 (324) = 15.43 ohms. Applying 220 volts on the same heater whose resistance is 15.43 ohms results in this new heater wattage rating. W = E (squared)/R = 220 x 220 (48400)/15.43 = 3137 watts. W = watts, I = amperage, R = resistance in ohms and E = voltage.

Yes, voltage effects the output of electric heaters. The wattage output rating of the heater will not be reached due to the lower applied voltage. For example if the heater is 5000 watts at 277 volts, the current is I = W/E 5000/277 = 18 amps. The resistance of the heater is R = W/I (squared) = 5000/18 x 18 (324) = 15.43 ohms. Applying 220 volts on the same heater whose resistance is 15.43 ohms results in this new heater wattage rating. W = E (squared)/R = 220 x 220 (48400)/15.43 = 3137 watts. W = watts, I = amperage, R = resistance in ohms and E = voltage.

Look on the heater and see what amps it is pulling. That will determine the wire size and breaker size. It must be on a dedicated circuit. 15 amps = AWG # 14 wire with 15 amp breaker 20 amps = AWG # 12 wire with 20 amp breaker 30 amps = AWG # 10 wire with 30 amp breaker 40 amps = AWG # 8 wire with 40 amp breaker

Micheal Jackson is a hip hop and r&b singer.And he made the song"5000 watts"

Not if the furnace exceeds 5000 watts.

The average size water tank is 4500 watts. The generator's supply will be large enough to operate the water tank. Larger tanks over 5000 watts will not heat correctly.

There should be two outputs on the 30 A breaker. You will need 10 AWG wire with 3-conductors and ground. Typically the wire colors will be Black, Red, White and (Green or bare). Connect black to one output of breaker and red to other output. Connect white to the white buss bar in main panel and green/bare to ground buss bar. At heater end connect the red and black to the 240 V leads, white to white and green/bare to the heater case.

To find amps if watts and volts are known, use the formula; watts / volts = amps or 5000 / 240 = 20.83 amps

A 5kw heater draws just that, 5kw or 5000 w. If you have that switched on high, well I do not know what your supplier charges per kw hour, I am glad its not me paying.

5KW

This is not recommended. The heater will operate at more than its given specified wattage. A 208 volt heater run off 220 volts will have an output increase by 11.87 percent. Similarly, a 220 volt heater can be run off of 208 but the wattage will be reduced by 10.61%. The calculations, using Ohms' Law, are shown below.Watts = volts x amps (W = V x I) and I = W / V so, if we take a 2000 watts heater designed to run on 208 volts, I = 2000 / 208 = 9.6 ampsResistance = volts / amps (R = V / I) so the heater's resistance is 208 / 9.6 = 21.632 ohmsAmps = volts / resistance (I = V / R) so, running on 220 volts, I = 220 / 21.632 = 10.17 ampsW = 220 x 10.17 = 2237 watts, which is an increase of 2237/2000 = 11.87%.W = V x I and I = W / V so, if we take a 2000 watts heater designed to run on 220 volts, I = 2000 / 220 = 9.09 ampsR = V / I so the heater's resistance is 220 / 9.09 = 24.2 ohmsI = V / R so, running on 208 volts, I = 208 / 24.2 = 8.595 ampsW = 208 x 8.595 = 1787.76 watts, which is a decrease of ( 2000-1787.76 ) / 2000 = 10.61%.