It decays by electron capture to an excited state of tellurium-125.
Iodine-125 (53125I) decays by beta+ decay, with a half-life of 59.4 days, to tellurium-125 (52125Te), which is stable and non-radioactive.
Iodine is used to treat prostate cancer and brain damage
We know that iodine-131 will undergo beta minus decay, and an electron will appear as a result. (An electron antineutrino will also be produced, but we don't want to go there in this topic.)
8.02 days
iodine
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
Iodine 131 -> Xe 131 + e-
Here is the equation for the beta minus decay of iodine-131: 53131I => 54131Xe + e- + ve The iodine-131 undergoes a transformation when a down quark within a neutron in its nucleus changes into an up quark. This change is mediated by the weak interaction, or weak force. The neutron then becomes a proton, and an electron is created and ejected from the nucleus along with an antineutrino. To learn more, use the link below to the related question, "What is beta decay?"
The time required is 24.06 days. The half life of iodine 131 is 8.02 days.
Never. As a simple exponential-decay problem, it can get as small as you want if you're willing to wait long enough, but it never reaches zero.
This is a chemical element. You can find the how many electron in a single atom by using a periodic table.
The element Iodine has 53 protons, 53 electrons, and 74 neutrons