To find the grams of CaCO3 in 4.5 moles, you would first calculate the molar mass of CaCO3 (40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for O), which totals 100.09 g/mol. Then, multiply this molar mass by the number of moles (4.5) to get the grams of CaCO3. So, 4.5 moles of CaCO3 is equivalent to 450.405 grams.
The formula for limestone is CaCO3, which represents calcium carbonate. It is a sedimentary rock that is composed mainly of the mineral calcite.
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
CaCo3=Cao+Co2
CaCO3 is insoluble in water.
the answer is DECOMPOSITION... and that is the answer not CaCO3
CaCO3 is the chemical formula for calcium carbonate.
To find the number of moles in 250 g of CaCO3, divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. So, 250 g ÷ 100.09 g/mol ≈ 2.50 moles of CaCO3.
Molar mass of CaCO3 = 100.0869 g/mol
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
The IUPAC name for CaCO3 is calcium carbonate.