CaCO3 is the chemical formula for calcium carbonate.
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
It is CaCO3.....it is the same as marbleFormula: CaCO3
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
the answer is DECOMPOSITION... and that is the answer not CaCO3
CaCO3 is insoluble in water.
CaCo3=Cao+Co2
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
Molar mass of CaCO3 = 100.0869 g/mol
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
The balanced chemical equation for the reaction between Na2CO3 and CaCl2 to form CaCO3 and NaCl is: Na2CO3 + CaCl2 -> CaCO3 + 2NaCl. Therefore, the coefficients are 1, 1, 1, and 2 for Na2CO3, CaCl2, CaCO3, and NaCl respectively.