To find the grams of CaCO3 in 4.5 moles, you would first calculate the molar mass of CaCO3 (40.08 g/mol for Ca, 12.01 g/mol for C, and 16.00 g/mol for O), which totals 100.09 g/mol. Then, multiply this molar mass by the number of moles (4.5) to get the grams of CaCO3. So, 4.5 moles of CaCO3 is equivalent to 450.405 grams.
The formula for limestone is CaCO3, which represents calcium carbonate. It is a sedimentary rock that is composed mainly of the mineral calcite.
caco3 is solid form. its density is high so caco3 is not soluble in water. but co2 mix in water befuor the mix in caco3 . so caco3 is soluble after mixing the co2 .
CaCo3=Cao+Co2
CaCO3 is insoluble in water.
the answer is DECOMPOSITION... and that is the answer not CaCO3
To find the number of moles in 250 g of CaCO3, divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. So, 250 g รท 100.09 g/mol โ 2.50 moles of CaCO3.
Molar mass of CaCO3 = 100.0869 g/mol
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
CaCO3 + 2HCl --> CaCl2 + H2O + CO2
The IUPAC name for the compound CaCO3 is calcium carbonate. In this compound, "Ca" represents the element calcium, while "C" represents the element carbon, and "O" represents the element oxygen. The subscript numbers indicate the ratio of each element in the compound, with one calcium atom, one carbon atom, and three oxygen atoms present.
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.