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How many distinguishable permutations of letters are possible in the word class?
120?
How many different five letter permutations can be formed fron the letters of the word ditto?
The only five letter word that can be made with those letters is 'ditto'.Other words that can be made with the letters in 'ditto' are:dodotIidittotot
How many distinguishable 11 letter words can be formed from the word Mississippi?
Just one - Mississippi. I checked the Scrabble dictionary and Webster's Second International dictionary (around 250,000 words in each).
How many words can be made out of the word hospitality?
165
How many words can be made out of the word January?
Words that can be made with the letters in 'January' are:aajaranaurajarjayjurynarynayrayrayrunurnyarn
How many distinguishable permutations of letters are in the word queue?
three
How many distinguishable permutations are there in the word letters?
7 factorial
How many distinguishable permutations are there for the word ALGEBRA?
There are 7 factorial, or 5,040 permutations of the letters of ALGEBRA. However, only 2,520 of them are distinguishable because of the duplicate A's.
How many distinguishable permutations of letters are possible in the word class?
120?
What are number of distinguishable permutations in the word Georgia?
2520.
In how many ways can all the letters in the word mathematics be arranged in distinguishable permutations?
The word mathematics has 11 letters; 2 are m, a, t. The number of distinguishable permutations is 11!/(2!2!2!) = 39916800/8 = 4989600.
How many permutations are in the word October?
There are 7 factorial, or 5,040 permutations of the letters of OCTOBER. However, only 2,520 of them are distinguishable because of the duplicate O's.
How many permutations are in the word arithmetic?
10! permutations of the word "Arithmetic" may be made.
Find the number of distinguishable permutations of letters in the word appliance?
The distinguishable permutations are the total permutations divided by the product of the factorial of the count of each letter. So: 9!/(2!*2!*1*1*1*1*1) = 362880/4 = 90,720
What is the number of distinguishable permutations of the letters in the word GLASSES?
The solution is count the number of letters in the word and divide by the number of permutations of the repeated letters; 7!/3! = 840.
How many distinguishable permutations are there of the letters in the word effective?
The number of permutations of the letters EFFECTIVE is 9 factorial or 362,880. To determine the distinct permutations, you have to compensate for the three E's (divide by 4) and the two F's (divide by 2), giving you 45,360.
How may distinguishable permutations are possible with all the letters of the word ellises?
We can clearly observe that the word "ellises" has 7 letters and three pairs of letters are getting repeated that are 'e','l' and 's'. So, Number of distinguishable permutations = 7!/(2!2!2!) = 7 x 6 x 5 x 3 = 630.
