The conversion factor you need for this problem is Avogadro's number.
(6.02 x 1023 atoms germanium/1 mole germanium) = 1
... OR ...
(1 mole germanium/6.02 x 1023 atoms germanium) = 1
Since you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from atoms Ge, so this goes in the denominator (on the bottom).
atoms Ge1 mole Ge = moles Ge6.02E+23 atoms Ge
To convert atoms of germanium to grams of germanium, you would need to multiply by the molar mass of germanium. The molar mass of germanium is approximately 72.63 grams per mole. This conversion factor allows you to go from the atomic scale to the macroscopic scale of grams. Simply multiply the number of atoms of germanium by 72.63 g/mol to obtain the mass in grams.
The conversion factor you need for this problem is the atomic mass of germanium.72.6 gram germanium = 1 mole germaniumSince you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from grams Ge, so this goes in the denominator (on the bottom).grams Ge1 mole Ge = moles Ge72.6 gram Ge
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
Avogadro's constant is 6.02*10^23. This number represents the number of representative particles (atoms, molecules, or formula units) in one mole. To solve your question, we simply multiply Avogadro's constant by the number of moles. 6.02*10^23 * 2.3 = 1.38*10^24
42.394 grams.
To convert atoms of germanium to grams of germanium, you would need to multiply by the molar mass of germanium. The molar mass of germanium is approximately 72.63 grams per mole. This conversion factor allows you to go from the atomic scale to the macroscopic scale of grams. Simply multiply the number of atoms of germanium by 72.63 g/mol to obtain the mass in grams.
The conversion factor you need for this problem is the atomic mass of germanium.72.6 gram germanium = 1 mole germaniumSince you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from grams Ge, so this goes in the denominator (on the bottom).grams Ge1 mole Ge = moles Ge72.6 gram Ge
The conversion factor you need for this problem is the atomic mass of germanium.72.6 gram germanium = 1 mole germaniumSince you want to end up in units of moles of Ge, this goes in the numerator (on top). You want to convert from grams Ge, so this goes in the denominator (on the bottom).grams Ge1 mole Ge = moles Ge72.6 gram Ge
For this you do not have to have an Atomic Mass. Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.2.5 moles × (6.02 × 1023 atoms) = 1.51 × 1024atoms in 2.5 moles
The conversion factor you need for this problem is Avogadro's number.(6.02 x 1023 atoms iron/1 mole iron) = 1... OR ...(1 mole iron/6.02 x 1023 atoms iron) = 1Since you want to end up in units of atoms of Fe, this goes in the numerator (on top). You want to convert from moles Fe, so this goes in the denominator (on the bottom).moles Fe6.02E+23 atoms Fe = atoms Fe1 mole Fe
To convert grams of oxygen to atoms of oxygen, you would multiply by Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol. This conversion allows you to move from the unit of mass (grams) to the unit of atoms.
There is no direct relationship between atoms of boronand grams of boron. Use Avogadro's number to convert atoms to moles, and the atomic mass to convert moles to grams.Since you are converting from atoms B, this goes in the denominator (on the bottom) of the first factor. You want to end up in units of grams of B, so this goes in the numerator (on the top) of the last factor.atoms B1.00 mole B10.8 gram = g B6.02E+23 atom B1.00 mole BNote that the units atoms boron "cancel out" in the first factor and you are left in units of moles. Moles cancel outin the second factor and the final units are grams boron.
For this problem you don't need the atomic mass of the element. If you want to convert moles to atoms, you need to take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023. Divide by one mole for units to cancel.9.00 moles C × (6.02 × 1023 atoms) = 5.42 × 1024 atoms C
For this you don't need to have the atomic mass. Take the number of atoms and divide it by Avogadro's constant, 6.02 × 1023. Multiply by one mole for units to cancel.20.00 atoms Au / (6.02 × 1023 atoms) = 3.32 × 10-23 moles of Au
Avogadro's constant is 6.02*10^23. This number represents the number of representative particles (atoms, molecules, or formula units) in one mole. To solve your question, we simply multiply Avogadro's constant by the number of moles. 6.02*10^23 * 2.3 = 1.38*10^24
1.203mol
For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.3.00 moles H2 × 2.02 = 6.06 grams H2