For this you need the atomic (molecular) mass of H2. Take the number of moles and multiply it by the Atomic Mass. Divide by one mole for units to cancel.
3.00 moles H2 × 2.02 = 6.06 grams H2
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There are approximately 1.806 x 10^24 atoms in 3 moles of helium. This calculation is based on Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole.
There are approximately 1.8 x 10^24 atoms in 3.0 moles of helium. This is calculated using Avogadro's number (6.022 x 10^23) as the conversion factor between moles and atoms.
6,1x10-3 moles of carbon 36,7350592277.1020 atoms.
There are 2 moles of atoms in 12.0 grams of helium. Helium has a molar mass of 4 g/mol and each mole contains 6.02 x 10^23 atoms. Calculating the number of moles: 12 g / 4 g/mol = 3 moles. And then, 3 moles * 6.02 x 10^23 atoms/mol = 1.81 x 10^24 atoms.
3 x 6.02E23 molecules.
.7 g= .17 mol = 1.05 x 10^23 atoms