Yes, CHOOH is methanoic acid - it is an organic acid because it contains the "COOH"functional group. The carbon atom has one bond with the hydrogen atom, and one bond with the OH molecule, and finally a double bond with the oxygen.
HCHO2 is a weird way of writing formic acid, which is usually written CHOOH. As you might be able to guess from it's name, it's an acid. KOH is a base. Like most acids and bases, they react to make water, and a salt. The salt in this case would be potassium formate.
Solute, because it is the minor component in the solution and it is what dissolves in the solvent. For example: Salt Water - The salt is the solute that dissoles in the solvent, which is water.
An adjective is a word that best describes the salt; for example much salt, little salt, or some salt.
In a salt solution, the salt is the solute and the substance in which the salt dissolves is the solvent. For example, in a saltwater solution, salt (sodium chloride) is the solute and water is the solvent.
Yes, CHOOH is methanoic acid - it is an organic acid because it contains the "COOH"functional group. The carbon atom has one bond with the hydrogen atom, and one bond with the OH molecule, and finally a double bond with the oxygen.
CHOOH and NaCHOO
The formic acid is a weak acid.
By definition, any covalent chemical is a compound. Formic acid is a covalent chemical (specifically, a monoprotic organic acid CHOOH).
HCHO2 is a weird way of writing formic acid, which is usually written CHOOH. As you might be able to guess from it's name, it's an acid. KOH is a base. Like most acids and bases, they react to make water, and a salt. The salt in this case would be potassium formate.
Salt water is a solution of salt, containing of course salt.
salt is not from salt water
No. salt water is salt water. it already has salt in it
acidic salt basic salt normal salt
Salt. Nothing else added. Salt is a crystal and rock salt is salt that is not made into a fine grained salt.
the salt is the solute
NaCl is commonly known as table salt - Na=Sodium Cl=Chloride