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What will the stopping distance be for a 2000 kg car if -2000 n of force are applied when the car is traveling 20 ms?
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∙ 6y ago
200 m
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What will the stopping distance be for a 3000kg car if 3000 N of force are applied when the car is traveling 10 ms?
The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.
What will the stopping distance be for a -2000 N of force are applied when the car is traveling 20 ms?
To calculate the stopping distance, we need more information such as the mass of the car and the acceleration. The force alone is not sufficient to determine the stopping distance.
What will the stopping distance be for a 3000kg car if -3 000 N of force are applied when the car is traveling 10 ms?
50m
What will the stopping distance be for a 3000kg car if -3000 N of force are applied when the car is traveling 10ms?
The stopping distance can be calculated using the equation: stopping distance = (initial velocity^2) / (2 * deceleration). The deceleration can be calculated using the formula: deceleration = force / mass. Plugging in the values and calculating will give you the stopping distance.
What will the stopping distance be for a 1000-kg car if -2000 N of force are applied when the car is traveling 10 ms?
25 m
What will the stopping distance be for a 2000-kg car if -2000 N of force are applied when the car is traveling 20 ms?
200 m
What will the stopping distance be for a 1,000-kg car if -2,000 N of force are applied when the car is traveling 10 m/s?
25 m
What will the stopping distance be for a 1000 kg car if -2 000 N of force are applied when the car is traveling 10 ms?
25 m
What will the stopping distance be for a 3000-kg car if -3000 N of force are applied when the car is traveling 10 ms?
To calculate the stopping distance, we need to know the deceleration of the car, which can be determined using the equation force = mass x acceleration. In this case, the deceleration would be -1 m/s^2. Using the equation stopping distance = (initial velocity)^2 / (2 x acceleration), we find the stopping distance to be 50 meters.
What will the stopping distance be for a kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, we need to first find the deceleration of the car using the formula: force = mass x acceleration. Given that force = -3000 N and mass = kg, we can find the acceleration. Once the acceleration is known, we can use the equation of motion: final velocity^2 = initial velocity^2 + 2 x acceleration x distance to calculate the stopping distance.
What will the stopping distance be for 3000-kg car if -3000 N of force are applied when the car is traveling 10ms?
To calculate stopping distance, you need to know the deceleration of the car. Here, deceleration can be calculated using Newton's second law: deceleration = force / mass. With the given force of -3000 N and mass of 3000 kg, the deceleration would be -1 m/s^2. Using the equation of motion, final velocity^2 = initial velocity^2 + 2 * acceleration * distance, you can calculate the stopping distance.
What is the transfer of energy that occurs when a force is applied over distance?
The transfer of energy that occurs when a force is applied over a distance is called work. Work is calculated as the product of the force applied and the distance over which the force is applied in the direction of the force.
