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50m

Q: What will the stopping distance be for a 3000kg car if -3 000 N of force are applied when the car is traveling 10 ms?

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The stopping distance for a 3000kg car if 3000 N of force is applied when the car is traveling 10 ms is 50 meter. This is based on Newton's second law of force.

60000

3 tonnes

Force = mass X acceleration, F=ma=3000kg X 6m/s2=18000kgm/s2=18 kilonewtons

3000 Kg = 3 tonnes.

3000kg. kilograms is a measurement for mass.

3000kg = 6,613lb 13.9oz

3000kg = 6,613lb 13.9oz

round about 3000kg

3000kg is 3 tonnes.

F=m*a a=F/m = 300N/3000kg=0.1m/s^2

3000kg is 3 billion milligrams.