Q: In an isolated system two cars each with a mass of 1500 kg collide Car 2 is initially at rest while Car 1 was moving at 5 ms What is their final speed?

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10,000

10,000 kg-m/s

10,000 kg-m/s

10,000 kg-m/s

They move with a speed of 3 ms^-1.

They move with a speed of 3 ms^-1.

5 m/s APPEX ;)

Law of Conservation of Momentum: The total momentum after the collision is equal to the total momentum before the collission.

Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.

To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.

Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.

20 kg-m/s