10,000
10,000 kg-m/s
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
The total momentum before the collision is 10,000 kg m/s (1000 kg * 10 m/s) in the direction of Car 2's initial velocity. Since the system is isolated, momentum is conserved. After the collision, the total momentum is still 10,000 kg m/s, but now shared between the two cars.
Law of Conservation of Momentum: The total momentum after the collision is equal to the total momentum before the collission.
Magnitude of momentum before collision = (10 kg x 5 m/s) - (10 kg x 3 m/s) = 20 kg m/s. Magnitude of momentum after collision (assuming completely inelastic collision) = 20 kg m/s. Therefore, the magnitude of their combined momentum after collision will be 20 kg m/s.
10,000 kg-m/s
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
Their speed after the collision would be 5 m/s. This can be calculated using the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision in an isolated system. Since Car 1 was initially at rest (0 m/s) and Car 2 was moving at 10 m/s, their total momentum before the collision would be m * v = 1000 kg * 10 m/s = 10000 kgā m/s. After the collision, this total momentum would be divided between the two cars, resulting in a speed of 5 m/s for the combined system.
10 m/s
The velocity of mass m after the collision will depend on the conservation of momentum. If the system is isolated and no external forces act on it, the momentum before the collision will equal the momentum after the collision. So, you will need to calculate the initial momentum of the system and then use it to find the final velocity of m.
Their speed after colliding will be 5 m/s. This can be calculated using the principle of conservation of momentum, where the total momentum before the collision is equal to the total momentum after the collision.