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Q = MC(delta T). So, the change in temperature is equal to Q/MC. This expands to 259/(25 * 4.18). The final temperature is 24.48 degrees Celsius.

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9y ago
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9y ago

The increase in temperature can be measured by the following formula Q=mass*specific heat capacity*(change in temperature). 5000=100*4.18*(OT-20). By solving for OT, we get the answer as 32 degree celcius.

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11y ago

Using the formula for transfering heat: q=mc(dT), where

q = heat

m = mass of the water

c = specific heat capacity of water (4.184 J/g.oC, or 1 cal/g.oC)

dT = "delta" T, the change in temperature, T2-T1

q=(100g)(4.184J/g.oC)(82oC - 25oC) = (418.4J/oC)(57oC) = 24,000 J, or 24kJ

[Note: There are only 2 significant figures in 25oC and 82oC, so the answer can only have 2 significant figures.]

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10y ago

q=mcdeltat

25,100J=100g*4.18*deltaT

25+deltat=answer

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9y ago

At a pressure of 1 atmosphere, it is approximately 1500 small calories or gram calories (cal). This is equivalent to approx 1.5 large calories or food calories (Cal).

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13y ago

53.8 degrees

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14y ago

150 gm of water at 60 degrees

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11y ago

24.5

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Q: How much heat is required to raise 100 grams of water from25c to 82c?
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