What is the probability of drawing the ace of spades?

Answer 1

USING PERMUTATIONS AND COMBINATIONS

total number of cases : 52C13

favorable cases : (52-1)C13 = 51C13

P (of not drawing an ace of spades) = 51C13/52C13

= 3/4

odds against this question is : 3/(4-3)

= 3/1 [ANS.]

Answer 2

Since an ace is a subset of one of the spades, we start off with the assumption that in those spades, they won't pick an ace. Therefore:

(13 - 1)/52 = 12/52 = 3/13

Now, the probability of getting an ace is 4/51.

Multiplying these together, we have: 3/13(4/51) = 4/221.

Now, we need to figure out the probability of it having the ace in the spade. The probability of that is 1/52. If that is true, then the probability of grabbing another ace is 3/51 = 1/17! Thus:

1/52(1/17) = 1/884

Adding we have:

4/221 + 1/884 = 16/884 + 1/884 = 17/884 = 1/52.

Answer 3

Straight off the deck, your chances of drawing the Ace of Spades is 1 in 52 or about 1.9% (1/52x100 per cent).

In a 7 card draw, you have a 7 in 52 chance of drawing an Ace of Spades or roughly 18% (7/52x100 per cent).

It's simple math...

Answer 4

Assuming the deck used is a well shuffled standard 52-card deck, there are 48 cards that are not '9' cards out of 52 total, so the probability is 48/52 or 12/13 or ~92%.