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This is a match problem which is easily solved with the match formula of a2 + b2 = c2.

65 ft2 + 65 ft2 = 8450 ft2

The square root of 8450 ft2 is 91.92 ft

So, 2nd base is 92.92 ft from the back of home plate on a field with 65 ft bases paths.

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Wiki User

13y ago

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More answers

pythagorean theorem

4900 + 4900= c^2

9800=c^2

98.994...

it's about 99 feet

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Wiki User

14y ago
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It is 65 times the square root of 2 feet. Rounded to the nearest hundredth of a foot, it is 91.92 feet.

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Wiki User

14y ago
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From the pythagorean theorem

x^2 = 65^2 +65^2

x = 91.924 ft

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Wiki User

14y ago
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pythagorean theorem applies: a^2 + b^2 = c^2

(60)(60) + (60)(60) = 7200

sq root 7200 = ~85 ft

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Wiki User

13y ago
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Approximately 91.9 feet.

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Wiki User

16y ago
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91.

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Anonymous

4y ago
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Q: How far is 2nd base to home plate using 70 foot bases?
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