The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J·s), and f is the frequency. Rearranging the formula to solve for frequency gives f = E/h. Substituting the given energy of 3.26 x 10^-19 J into the formula gives a frequency of approximately 4.92 x 10^14 Hz.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the photon. Plugging in the values, the energy of a photon of red light with a frequency of 4.48 x 10^14 Hz is approximately 2.98 x 10^-19 Joules.
The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.
The energy of a photon can be calculated using the formula E = h * f, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of the photon. Thus, for a frequency of 5 x 10^12 Hz, the energy of the photon would be 3.31 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 6 x 10^12 Hz is approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J s) and f is the frequency of the photon. So, for a photon with a frequency of 6 x 10^12 Hz, the energy would be approximately 3.98 x 10^-21 Joules.
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the photon. Plugging in the values, the energy of a photon of red light with a frequency of 4.48 x 10^14 Hz is approximately 2.98 x 10^-19 Joules.
The energy of the electron increased by absorbing the photon with that frequency. Energy of a photon is directly proportional to its frequency, so a photon with a frequency of 4 x 10^15 Hz carries a specific amount of energy, which was transferred to the electron upon absorption.
The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
The frequency of a photon can be calculated using the formula E = hf, where E is the energy of the photon, h is Planck's constant (6.63 x 10^-34 J*s), and f is the frequency. Rearranging the formula to solve for frequency gives f = E / h. Plugging in the values, we find that the frequency of a photon with an energy of 3.38 x 10^-19 J is approximately 5.10 x 10^14 Hz.
The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 4 x 10^7 Hz is approximately 2.65 x 10^-26 Joules.
The energy carried by a photon can be calculated using the equation E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. Plugging in the values, the energy of a photon with a frequency of 5.71 x 10^14 Hz would be approximately 3.78 x 10^-19 Joules.
the energy of a photon is h times f
The energy of a photon is given by ( E = hf ), where ( h ) is the Planck constant and ( f ) is the frequency of the photon. Rearranging the formula gives ( f = E / h ). Plugging in the given energy value and the Planck constant, the frequency of the photon is approximately 3.01 x 10^22 Hz.