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From a velocity-time graph, you can calculate the acceleration by finding the slope of the graph at a certain point. The area under the graph represents the displacement of the object. You can also determine the direction of motion based on the slope of the graph (positive slope indicates motion in one direction, negative slope indicates motion in the opposite direction).

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Q: What can you calculate from velocity time graph?
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How to find the velocity of a position-time graph?

To find the velocity of a position-time graph, you calculate the slope of the graph at a specific point. The slope represents the rate of change of position with respect to time, which is the velocity. The steeper the slope, the greater the velocity.


How can one calculate velocity from a position-time graph?

To calculate velocity from a position-time graph, you can find the slope of the line tangent to the curve at a specific point. This slope represents the instantaneous velocity at that point. Alternatively, you can calculate the average velocity over a specific time interval by finding the change in position divided by the change in time.


What is the method for finding the position of an object from a velocity-time graph?

To find the position of an object from a velocity-time graph, you need to calculate the area under the curve of the graph. This area represents the displacement of the object.


How can one determine the average acceleration from a velocity-time graph?

To determine the average acceleration from a velocity-time graph, you can calculate the slope of the line connecting the initial and final velocity points on the graph. This slope represents the average acceleration over that time interval.


How do you calculate deceleration on a velocity time graph?

Deceleration on a velocity-time graph is calculated by finding the slope of the line segment representing the decrease in velocity. The formula for deceleration is given by the change in velocity divided by the time taken for the velocity to change. It indicates how quickly the object is slowing down.