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We're not sure of the solution, so we'll post the work here, and let others

tear it apart:

Sound intensity is proportional to the inverse square of the distance from the source.

So the new sound intensity is ( 1/0.67 )2 times the original value.

db = 10 log(P2/P1) = 10 log (1/0.67)2 = 20 log (1/0.67) = -20 log (0.67) =

+3.479 dB

Check:

(all together now . . . everybody sing, dance, and wave your hands in the air)

That sounds about right . . . we know that 0.707 is 1/2 sqrt(2),

which would produce a change of 3 dB.

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