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The period of a pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum (0.500 m in this case), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, the period of the pendulum with a length of 0.500 m can be calculated.
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What would be the period of a1.0 m length pendulum if it were oscillating on the moon?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. On the moon, the acceleration due to gravity is approximately 1.625 m/s^2, so the period of a 1.0 m length pendulum would be T = 2π√(1.0/1.625) ≈ 3.58 seconds.
What is the period of a 25 kg pendulum with a length of 45 m?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, T = 2π√(45/9.81) ≈ 9.0 s.
What is pendulum length?
The pendulum length is the distance from the point of suspension to the center of mass of a pendulum. It affects the period of the pendulum's swing, with longer lengths typically resulting in longer periods. A longer pendulum length will generally have a slower swing compared to a shorter length.
What is the length of a pendulum that has a period of 0.7 s?
The length of a pendulum with a period of 0.7 seconds can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula gives L = (T^2 * g) / (4π^2). Substituting T = 0.7 s and g = 9.81 m/s^2, the length of the pendulum is approximately 0.46 meters.
What pendulum length in Nairobi would have a time period of 1s?
Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.
What is the length of a pendulum that has a period of 4.89 seconds?
5.94 m
What would be the period of a1.0 m length pendulum if it were oscillating on the moon?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. On the moon, the acceleration due to gravity is approximately 1.625 m/s^2, so the period of a 1.0 m length pendulum would be T = 2π√(1.0/1.625) ≈ 3.58 seconds.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
What is the period of a 25 kg pendulum with a length of 45 m?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, T = 2π√(45/9.81) ≈ 9.0 s.
What is pendulum length?
The pendulum length is the distance from the point of suspension to the center of mass of a pendulum. It affects the period of the pendulum's swing, with longer lengths typically resulting in longer periods. A longer pendulum length will generally have a slower swing compared to a shorter length.
What is the length of a pendulum with a period of 4.48ses?
The length of a pendulum can be calculated using the formula L = (g * T^2) / (4 * π^2), where L is the length of the pendulum, g is the acceleration due to gravity (approximately 9.81 m/s^2), T is the period of the pendulum (4.48 s in this case), and π is a mathematical constant. By substituting the values into the formula, the length of the pendulum with a period of 4.48 s can be determined.
What time required in 1 oscillation of pendulum?
The time required for one complete oscillation (or swing) of a pendulum is known as its period. The period of a simple pendulum depends on its length and the acceleration due to gravity. The formula to calculate the period of a pendulum is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (approximately 9.81 m/s^2).
What is the length of a pendulum that has a period of 0.7 s?
The length of a pendulum with a period of 0.7 seconds can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula gives L = (T^2 * g) / (4π^2). Substituting T = 0.7 s and g = 9.81 m/s^2, the length of the pendulum is approximately 0.46 meters.
What pendulum length in Nairobi would have a time period of 1s?
Assuming a gravitational acceleration of 9.81 m/s^2, a pendulum in Nairobi with a length of approximately 0.25 meters would have a time period of around 1 second. This is calculated using the formula T = 2π√(L/g), where T is the time period, L is the length of the pendulum, and g is the gravitational acceleration.
What is the period of a 0.85m long pendulum?
The period of a pendulum can be calculated using the equation T = 2π√(l/g), where T is the period in seconds, l is the length of the pendulum in meters, and g is the acceleration due to gravity (9.81 m/s^2). Substituting the values, the period of a 0.85m long pendulum is approximately 2.43 seconds.
What is the period of a simple pendulum 45 cm long on the Earth?
The period of a simple pendulum can be calculated using the formula T = 2π * sqrt(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. On Earth, the value of g is approximately 9.81 m/s^2. Converting the length of the pendulum to meters (0.45 m), the period would be about 1.42 seconds.
How long must a simple pendulum be in order to have a period of one second?
A simple pendulum must be approximately 0.25 meters long to have a period of one second. This length is calculated using the formula for the period of a simple pendulum, which is T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. By substituting T = 1 second and g = 9.81 m/s^2, you can solve for L.
