It is 472.44 grams.
To find the mass of the block, first calculate its volume: 3.000 cm * 4.000 cm * 5.000 cm = 60.000 cm^3. Then, multiply the volume by the density of iron: 60.000 cm^3 * 7.874 g/cm^3 = 472.44 g. Therefore, the mass of the block is 472.44 grams.
There's no single answer to that, as ml is volume and mg is weight. Depending on the density of the substance the answer will be different.
The answer depends on the temperature and density of the substance. For example: 1 mL of 0 degrees C water weighs 999.87247956 mg. Therefore, 3 mL of the water would weigh: 3 * 999.87247956 mg = 2,999.61743868 mg
3 tenths of a kilogram is equivalent to 300 grams.
3000 grams is equivalent to 3 kilograms.
3000 ml = 3 liters There are 1000 milliliters in a liter.
In whole numbers of feet 3000 long by 1 wide. I suspect that more accurate wording might help answerers.
Specific gravity of gold = 19.3 (so density = 19.3 grammes per cubic centimetre) Volume of gold block = 20*15*10 = 3000 cubic centimetre Mass of gold block = 3000*19.3 = 57900 grammes = 57.9 kilogrammes.
3000
The density of the object would be 3000 g/ml. Density is calculated by dividing the mass of an object by its volume. In this case, 15000 g / 5 ml = 3000 g/ml.
0.923076 because 3000 divided by 3250 is 0.923076 recurring.
There are 5,280 feet per mile, so you would need to run (5280 / 3000) 1.76 blocks.
There's no single answer to that, as ml is volume and mg is weight. Depending on the density of the substance the answer will be different.
1,640.42/(3,000 + width of the block in feet)times.If the block is 3,000 feet long and only one foot wide,then only once around the block = 1.829 kilometer.
It depends on the density of the 3000 milligrams. The gram is a unit of mass, while the liquid ounce is a unit of volume. The two are not directly convertible unless you know what material you are talking about.
The area of the base of a rectangular tank is 3000 square inches and the volume of the tank is 324000 cubic inches. Find the height of the tank in feet? V = Bh h = V/b h = 324,000 in3/3000 in2 h = 108 in Since 1 foot = 12 in, then 108 in are 9 ft (108/12). Thus the height of the tank is 9 ft.
If the volume of a triangular prism is 300 Cm, the dimensions can be regarded as V = L (A=Bx 1/2 x H). Therefore, we can assume the length to be 12cm, base to be 12 cm.
Without some indication of density for comparison, it is impossible to convert millilitres to kilograms.