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It is 472.44 grams.

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6y ago
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1mo ago

To find the mass of the block, first calculate its volume: 3.000 cm * 4.000 cm * 5.000 cm = 60.000 cm^3. Then, multiply the volume by the density of iron: 60.000 cm^3 * 7.874 g/cm^3 = 472.44 g. Therefore, the mass of the block is 472.44 grams.

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Q: Iron has a density of 7.874 gcm 3 What is the mass of a rectangular block of iron with dimensions of 3.000 cm by 4.000 cm by 5.000 cm?
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