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The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.

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What is Joules per gram per degree centigrade?

Joules per gram per degree Celsius is a measure of specific heat capacity, which represents the amount of energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius. It is a constant value unique to each substance and helps in determining how much heat energy is needed for temperature changes.


How much heat is required to raise the temperature of 15 kg of water from 22 degree centigrade to 35 degree centigrade?

The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate that the heat required is approximately 20910 Joules or 20.91 kJ.


What is the science definition for calorie?

A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.


How much energy required to heat 100 liters of 30 degree centigrade water to raise 135 degree centigrade?

The energy required to heat water can be calculated using the formula: Q = mcΔT, where Q is the energy in joules, m is the mass of water in kg, c is the specific heat capacity of water (4186 J/kg°C), and ΔT is the temperature change in °C. First, convert 100 liters of water to kg using the density of water (1 kg/L). Then, calculate the energy required using the given temperatures: ΔT = (135 - 30)°C. Substitute the values into the formula to find the energy needed.


What is the amount of energy required to raise temperature of one gram of water by one Celsius degree is called?

The amount of energy required to raise the temperature of one gram of water by one Celsius degree is called the specific heat capacity of water. It is approximately 4.18 joules per gram per Celsius degree.

Related Questions

1560 degree centigrade equals how much calorie?

You can't convert units of temperature to units of energy.


What is the word origin of the word calorie?

"Calorie" comes to us from Latin "calor", meaning "warmth". A calorie is the energy required to raise the temperature of one gram of water by one degree centigrade.


What is Joules per gram per degree centigrade?

Joules per gram per degree Celsius is a measure of specific heat capacity, which represents the amount of energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius. It is a constant value unique to each substance and helps in determining how much heat energy is needed for temperature changes.


How much heat is required to raise the temperature of 15 kg of water from 22 degree centigrade to 35 degree centigrade?

The specific heat capacity of water is 4.18 J/g°C. Using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature, we can calculate that the heat required is approximately 20910 Joules or 20.91 kJ.


What is the science definition for calorie?

A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.


100 g of water at 20 degree centigrade is mixed with 100 g of water at 5 degree centegrade the temperature of mixture will be?

The final temperature of the mixture will be between 5 and 20 degrees Celsius, closer to 5 degrees since a larger mass of water is at that temperature. To find the exact final temperature, you can use the principle of conservation of energy (Q lost = Q gained).


Time required to raise 1 degree centigrade in 1 liter of water?

To determine the time this will take, you need to know the rate at which heat is being added to the system. The specific heat capacity of a substance is the amount of energy required to raise the temperature of one gram of a substance one degree centigrade. For water at 25oC, the specific heat capacity is 4.184 J*g-1*oC-1. That is, if you have one gram of water, you must add 4.184 Joules of energy (heat) to raise the temperature one one degree centigrade. The time it takes for the temperature increase to happen depends on how quickly you add the 4.184 J. Adding heat at a rate of 1 Joule/second (which is equivalent to 1 Watt), it is easy to see that it will take 4.814 seconds to raise the temperature of the gram of water one degree centigrade. The first step to solving your problem, then, is to make your data units compatible with your known constants. We need to convert volume to mass. We do this by means of density. The density of liquid water at standard temperature and pressure is 1g/mL. 1L H2O *1000mL/1L *1g H2O/mL H2O= 1000g H2O Then, to find the amount of energy required to change the temperature of the mass, we use the specific heat. 1000g H2O *4.184J/(g*K)= 4184 J/oC Note the units on this last value. They give the amount of energy needed required per degree centigrade of change in the temperature. That is, it requires 4814J to change the temperature of 1000g H2O one degree centigrade. Given the time rate of heat transfer into the system, you can find the time required to make the change. If, for instance, your heat exchange rate is 5 Watts (J/s), you would have 4184 J/oC * 1 second/5 Joules = 836.8 s/oC This value allows you to calculate the time required for any change in temperature simply by multiplying the number of degrees centigrade temperature change. For one degree, we find 836.8 s/oC *1oC = 836.8s


What is to raise the temperature of 1 gram of water 1 degree Clntigrade?

Depends on how high you want to raise the gram of water ;).


How much energy required to heat 100 liters of 30 degree centigrade water to raise 135 degree centigrade?

The energy required to heat water can be calculated using the formula: Q = mcΔT, where Q is the energy in joules, m is the mass of water in kg, c is the specific heat capacity of water (4186 J/kg°C), and ΔT is the temperature change in °C. First, convert 100 liters of water to kg using the density of water (1 kg/L). Then, calculate the energy required using the given temperatures: ΔT = (135 - 30)°C. Substitute the values into the formula to find the energy needed.


Do you use thermal energy every day?

Yes, your body uses a thermal energy known as caloric energy called "calories." A calorie is the amount of thermal energy required to heat one gram of water by one degree centigrade.


The amount of heat energy required to raise the temperature of a unit mass of a material one degree is?

The amount of heat energy required to raise the temperature of a unit mass of a material by one degree is known as the specific heat capacity of that material. It is a constant value unique to each material and is typically measured in units of J/kg°C.


What is the amount of energy required to raise temperature of one gram of water by one Celsius degree is called?

The amount of energy required to raise the temperature of one gram of water by one Celsius degree is called the specific heat capacity of water. It is approximately 4.18 joules per gram per Celsius degree.