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Type your answer here... D0-D7 on 1st 8to1, D8-D15 on 2nd 8to1, S0,S1,S2 to both. The output from 1st 8to1 is D0 on the 2to1, the output from the 2nd 8to1 is D1 on the 2to1 and S3 to the 2to1. The 2to1 provides the final 16to 1 mutiplexed output, OK?

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Q: Construct a 16-to-1-line multiplexer with two 8-to-1-line multiplexers and one 2-t0-1-line multiplexer?
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