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Chitu and Nitu are characters in the Indian comic Nandan. Chitu is a mischievous young boy who often gets into trouble, while Nitu is his loyal and brave friend who helps him out of sticky situations. Together, they have many adventures and fun experiences in the comic.
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When was infosys started?
1981-Infosys was founded by N. R. Narayana Murthy, Nandan Nilekani, N. S. Raghavan, S. Gopalakrishnan, S. D. Shibulal, K. Dinesh and Ashok Arora
Who is the MD of infosys?
Infosys was co-founded by N. R. Narayana Murthy, Nandan Nilekani, N. S. Raghavan, S. Gopalakrishnan, S. D. Shibulal, in 1981. Vishal Sikka is currently the CEO and MD of the company.
How do you translate Patricia into Apache?
n n n n n n n n.
Current CEO of wipro infotech?
S Gopalakrishnan is the Present Ceo of the company.
What must you multiply n squared to get n cubed?
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
What is the number minus the product of 5 and the number?
N - 5*N = 4*N N - 5*N = 4*N N - 5*N = 4*N N - 5*N = 4*N
How do you do n squared plus n?
(n*n)+n
How long was all that jazz on Broadway for?
jazz has been around for a billion years
What country name with 8 letters?
Barbados \n . Botswana \n . Bulgaria \n . Cameroon \n . Colombia \n . Ethopia \n . Hondurus \n . Kiribati \n . Malaysia \n . Mongolia \n . Pakistan \n . Paraguay \n . Portugal \n . Slovakia \n .
What makes a Proscope a good investment for the Police Department?
n ,n ,n,n,,n ,,n,n
What is the sum of the first n numbers?
Assuming you mean the first n counting numbers then: let S{n} be the sum; then: S{n} = 1 + 2 + ... + (n-1) + n As addition is commutative, the sum can be reversed to give: S{n} = n + (n-1) + ... + 2 + 1 Now add the two versions together (term by term), giving: S{n} + S{n} = (1 + n) + (2 + (n-1)) + ... + ((n-1) + 2) + (n + 1) → 2S{n} = (n+1) + (n+1) + ... + (n+1) + (n+1) As there were originally n terms, this is (n+1) added n times, giving: 2S{n} = n(n+1) → S{n} = ½n(n+1) The sum of the first n counting numbers is ½n(n+1).
What is n squared minus n?
Algebraically it is written as ' n^(2) - n'. This factors to ' n(n-1)'.
