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It depends on the processor's register size, core frequence and some other stuff. Every instruction goes through a pipleline, if we are talking about an array of instructions. And for every instruction execution, these threads are passed and processed ALU (Arithmetic Logic Unit) etc. So there is no direct answer to this.

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Q: What time takes a single instruction to execute?
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What refers to the amount of time it takes a CPU to execute an instruction and store the result?

The execution cycle.


How much time is required to execute an instruction which takes single cycle for execution?

One cycle, in a computer, takes a time that is the reciprocal of the computer's clock rate - that which is expressed in MHz, or - more commonly nowadays - in GHz. Example: if your computer has a clock rate of 3 GHz, the time for a single cycle is (1 / 3 billion) seconds, i.e., 1/3 of a nanosecond, or 333 picoseconds.


What is the time to execute a 3 clock cycle instruction in a 25Mhz processor?

The time to execute a 3 clock cycle instruction in a 25MHz processor is 120ns. One clock cycle is 40ns, 1/25Mhz, so three of them are 120ns.


Is a process that allows the CPU to receive a single instruction and then execute it on multiple pieces of data rather than receiving the same instruction each time each piece of data is received?

"SIMD, which stands for 'single instruction, multiple data,' is a process that allows the CPU to receive a single instruction and then execute it on multiple pieces of data rather than receiving the same instruction each time each piece of data is received."(Pg. 434, A+ Guide to Managing and Maintaining Your PC)


What is the length of time it takes you to execute your action after you know a hazard will be a problem?

Reaction Time


Timing diagram of 8085?

Timing Diagram is a graphical representation. It represents the execution time taken by each instruction in a graphical format. The execution time is represented in T-states.Instruction Cycle:The time required to execute an instruction is called instruction cycle.Machine Cycle:The time required to access the memory or input/output devices is called machine cycle.T-State:The machine cycle and instruction cycle takes multiple clock periods.A portion of an operation carried out in one system clock period is called as T-state.MACHINE CYCLES OF 8085:The 8085 microprocessor has 5 (seven) basic machine cycles. They areOpcode fetch cycle (4T)Memory read cycle (3 T)Memory write cycle (3 T)I/O read cycle (3 T)I/O write cycle (3 T)Each instruction of the 8085 processor consists of one to five machine cycles, i.e., when the 8085 processor executes an instruction, it will execute some of the machine cycles in a specific order.The processor takes a definite time to execute the machine cycles. The time taken by the processor to execute a machine cycle is expressed in T-states.One T-state is equal to the time period of the internal clock signal of the processor.The T-state starts at the falling edge of a clock.


How 8085 timing diagram works based on each instruction?

Each instruction requires specific time for the execution of instruction and this time is called instruction cycle. Each instruction cycle consists 1 to 5 machine cycle -- opcode fetch, memory read, memory write, IO read, IO write and each machine cycle consist 3 to 6 T - states. Time required to execute 1 T-state = 1/ operating frequency of 8085 Microprocessor for example operating frequency = 2MHz then time required to execute 1 T-state = 0.5 uSec example: Calculate time required to execute instruction MOV C, A sol: This instruction has one machine cycle i.e. opcode fetch (In any instruction 1st cycle is always opcode fetch and opcode fetch consists 4 to 6 T state depend on the operation of particular instruction) so to execute MOV C, A required 4T states so time required to execute this instruction is 4*0.5usec = 2usec any other queries pls contect: nileshbahadure2000@yahoo.co.in example:Calculate the time required to execute LXI H,2000H sol:Here we have to draw opcode fetch and two memory reads as two bytes 00H and 20H have to be read from memory. i.e, opcode fetch+Memory reads *2(bytes address) =4+3+3 so to execute LXI H,2000H,the required T-states is 10T and time is 10*0.5usec=5usec


What is execution time in computing?

The time between a program starting and finishing. ie, the time it takes to execute the program.


How many clock cycle is needed to execute LDA?

It is a 3 byte instruction, with one byte for opcode and the other two for the 16bit address. It takes four machine cycles (one to fetch opcode, one to fetch lower order address, one to fetch higher order address and another one to fetch the data from the memory)... i.e. it takes 13 time states to perform the LDA instruction


What is single processing system?

The system that execute the one process at the time and the next job when process is completed it is called the single process system


Is the amount of time it takes to retrieve an instruction and complete the respective command?

i asked you idiot


Different between single task and multitasking?

In a 'single tasking' environment, only one task is given to the processor at a time & the processor takes millisecond to execute that task. For example, a student is writing a program which takes say, 10 minutes. During this time, the processor is sitting idle. When the program is given to the processor, it finishes its execution in a millisecond. This way, processor is wasting a lot of time which is a dawback in 'single tasking'. In a 'Multi tasking' environment, processor time is divided equally. For example, there are 4 tasks to execute. This is divided into 1/4 millisecond time for each job. This small part is called 'time slice'. Within this time slice, it will try to execute each job. If it can't, intermediate result will be stored in temporary memory. Once executing the fourth task, it will come back to the first task, in a circular manner. This is called 'round robin' method. The main difference is that, in single tasking, the processor time is wasted, but in multitasking, we can utilize the processor time in an optimum way.