Velocity extreme has the smaller cams than just velocity and i know the string is 57 3/4 on the extreme. I think 59 1/8 on reg. but not sure. No clue on cables mine are broke and i bought it that way.
v2 = v02 + 2a(delta x)v = sqrt(v02 + 2a(delta x))This is based on the assumption that there is constant acceleration.Another way to find velocity is using a little Calculus, this method is better since it does not assume constant acceleration, therefore this would work even if there is a change in acceleration.Since v = dx/dt, you can differentiate position with respects to time to find instantaneous velocity, given that you do know the time.And dv/dt = a, therefore dv = a x dt, integrate both sides you get velocity. This approach again requires the knowledge of time.
Never.Average velocity is total displacement (final position minus initial position) divided by the total time: vave = (xf-xi)/tAcceleration is the rate at which your velocity is changing or change in velocity over time: a= (vf-vi)/tThese two quantities may have the same numerical value but will never have the same units.Average velocity for a trip can equal instantaneous velocity at a certain point during the trip, however, at any time during a trip in which the velocity is constant or at half way through the total time of a trip where the acceleration is constant.
This site might help clear things up: http://id.mind.net/~zona/mstm/physics/mechanics/kinematics/ EquationsForAcceleratedMotion/Origins/Displacement/Origin.htm(Note: The site is all one line)
For analyzing projectile motion, you can use position-time graphs to track the object's trajectory over time, velocity-time graphs to analyze changes in speed during different phases of motion, and acceleration-time graphs to understand how acceleration influences the object's movement. These graphs can help visualize and evaluate various components of the projectile motion, such as trajectory shape, speed changes, and acceleration patterns.
The speed and direction of a wave
Summation of Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi XiXi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi Xi
Impulse XI 53 7/16 on a 28-30 draw length 56 3/8 on a 30-32 draw length
Divide the change in position, (total distance covered) by the time it took. Xf = xi +at a = xf-xi / t That is the definition of velocity, not acceleration. Acceleration is rate of change of velocity. (vfinal - vinitial)/t for constant acceleration so vf equals vi + at. Or a equals dV/dt otherwise.
Xf= Xi + Vxi(t) + (.5)(Ax)(t)2 where: Xf is the final position Xi is initial position Vxi is initial velocity Ax is average acceleration t is time Xi and Vxi will both be zero since the initial velocity and position are both zero. Xf = (0) + (0) + (.5)(9.8m/s2)(20)2 Xf = 1960 meters
Xf= Xi + Vxi(t) + (.5)(Ax)(t)2 where: Xf is the final position Xi is initial position Vxi is initial velocity Ax is average acceleration t is time Xi and Vxi will both be zero since the initial velocity and position are both zero. Xf = (0) + (0) + (.5)(9.8m/s2)(20)2 Xf = 1960 meters
To find the initial velocity of the basketball player at the start of the leap, we need to use the kinematic equation: v^2 = u^2 + 2as, where v is the final velocity (0 m/s at the peak of the jump), u is the initial velocity (what we need to find), a is acceleration due to gravity (-9.8 m/s^2), and s is the displacement (0.5 m). By substituting the known values into the equation and solving for u, we can find the initial velocity.
XI-XI-LXXXVIII 11-11-1988 = XI-XI-MCMLXXXVIII
the piecewise linear chaotic map is defined as follows: xi+1=Fpi(xi)= xi/pi if 0<=xi<pi (xi-pi)/(0.5-pi) if pi<=xi<0.5 Fp(1-xi) if xi>=0.5 where 0<=xi<1 and the control parameter 0<pi<0.5
xi
32
body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range
xi or XI are the Roman numerals for 11