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Well it will be where the wright of the overhang rod equals the weight of the rod plus the weight of the 10kg so we have 60kg total weight we will need 30 on each side so you will have 30kg of the rod weight on one side of the balance and 20 rod and 10 of the weight on the other so you have 20/50th or 2/5th of the rod weight on the side with the weight so 6m=2/5th * L where L is the length of the rod so 6*5/2=L or the rod is 15m long.

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15y ago
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Q: What is the lenght of the iron rodhaving weight 50kg and a weight of 10kg is attached at its one end it balances itself from a point 6m from the same end?
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