Eq.mass of K2MnO4 = Molar mass of K2MnO4/number of e- gain or loss in a redox reaction
so, Eq.mass of K2MnO4= 197/5=39.4
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The equivalent mass of K2MnO4 is calculated by dividing the molar mass by the change in oxidation state of the element being reduced or oxidized. For K2MnO4, the molar mass is 198.1 g/mol. Since the Mn in MnO4^- has an oxidation state of +7 in the permanganate ion and is reduced to +2 in Mn^2+, the change in oxidation state is 5. Therefore, the equivalent mass of K2MnO4 is 198.1 g/mol / 5 = 39.62 g/equiv.
The compound name for K2MnO4 is potassium permanganate.
In order to convert KMnO4 to K2MnO4, a reducing agent is typically needed. One common method involves using a reducing agent like a metal, such as zinc or iron, to react with KMnO4 in an acidic medium to produce K2MnO4.
In K2MnO4, the oxidation state of oxygen is -2, and the overall charge of the compound is -1. Given that potassium has a +1 oxidation state, the oxidation state of manganese (Mn) in this compound is +7.
The equivalent mass of sulfuric acid (H2SO4) is calculated as its molar mass divided by the number of replaceable hydrogen ions it can donate. Since sulfuric acid can donate 2 hydrogen ions (H+), the equivalent mass is half of the molar mass. Therefore, the equivalent mass of sulfuric acid is approximately 49 g/mol.
The molar mass of a substance is equal to its equivalent in daltons.