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Eq.mass of K2MnO4 = Molar mass of K2MnO4/number of e- gain or loss in a redox reaction

so, Eq.mass of K2MnO4= 197/5=39.4

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The equivalent mass of K2MnO4 is calculated by dividing the molar mass by the change in oxidation state of the element being reduced or oxidized. For K2MnO4, the molar mass is 198.1 g/mol. Since the Mn in MnO4^- has an oxidation state of +7 in the permanganate ion and is reduced to +2 in Mn^2+, the change in oxidation state is 5. Therefore, the equivalent mass of K2MnO4 is 198.1 g/mol / 5 = 39.62 g/equiv.

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10mo ago
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Q: What is the equivalent mass of K2MnO4?
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