NO
The balanced equation between magnesium and nitrogen to form magnesium nitride is: 3Mg + N2 -> Mg3N2.
Nitrogen gas (N2) consists of a covalent bond between two nitrogen atoms. This bond involves the sharing of electrons between the atoms, resulting in a stable molecule.
The N2 molecule contains a triple bond between the two nitrogen atoms, which results in a stable configuration with no unpaired electrons. The N2- ion, however, has a single unpaired electron due to the addition of an extra electron, making it paramagnetic.
When ammonia decomposes into its elements, it forms nitrogen gas and hydrogen gas as products. This decomposition reaction can be represented by the equation: 2 NH3 -> N2 + 3 H2.
The notation 2N typically means double the amount of a variable or object N. So, 2N is twice the value of N.
2n is 2 times n.
(n2 + 2n - 1) (n2 + 2n - 1) = n4 + 2n3 - n2 + 2n3 + 4n2 - 2n - n2 - 2n + 1 = n4 + 4n3 + 2n2 - 4n + 1 try with n = 5: (5 squared + 10 - 1) squared = 34 squared = 1156 with formula (5^4) + (4 *(5^3)) + (2 * (5^2)) - (4 * 5) + 1 = 625 + 500 + 50 - 20 + 1 = 1156
n is 2. To solve, do the division: . . . . . . . . .x2 +. 3x + (6-2n) . . . -------------------------- x-2 | x3 + x2 - 2nx + n2 . . . . .x3 -2x2 . . . . .-------- . . . . . . . .3x2 - 2nx . . . . . . . .3x2 - . 6x . . . . . . . .---------- . . . . . . . . . (6-2n)x + n2 . . . . . . . . . (6-2n)x - 2(6-2n) . . . . . . . . . ---------------------- . . . . . . . . . . . . . . . .n2 + 2(6-2n) But this remainder is known to be 8, so: n2 + 2(6-2n) = 8 ⇒ n2 - 4n + 4 = 0 ⇒ (n - 2)2 = 0 ⇒ n = 2
Take 5 out. If the missing signs are pluses, it becomes 5(n2 + 2n + 4) If the missing signs are minuses, it becomes 5(n2 - 2n - 4)
The nth term is given by: rn = n2 + 8
5 - 2n = 1 4 = 2n n = 2
2n - 3
-n2+2n+49
double the number n2 2n 2xn nx2
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence
It is abs(5 - 2n) = 1